Math / Data & Statistics

QuestionMean, Median, Mode \& Range
Find the mean, median, mode and range for each set of numbers. 1) $24,31,12,38,12,15$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 3) $53,13,34,41,26,61,34,13,69$
Mean : $\square$ $\square$ Mode : $\square$ Median :
Range : $\square$ 5) $92,63,22,80,63,71,44,35$ $\square$ Mean : Median : $\square$ Mode : $\square$ Range : $\square$ 7) $72,43,15,66,32,72,52,19,28,81$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 9) $12,46,32,18,26,41,46$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 2) $5,28,16,32,5,16,48,29,5,35$
Mean : $\square$ Median : $\square$ $\square$ 4) $85,58,72,85,46,93$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 6) $39,82,74,96,64,52,74$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 8) $40,90,36,68,90,11,88,54$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$ 10) $63,40,51,70,36,21,51,28,19$
Mean : $\square$ Median : $\square$ Mode : $\square$ Range : $\square$

Studdy Solution

STEP 1

What is this asking? We need to find the mean, median, mode, and range for a bunch of number sets. Watch out! Don't mix up mean, median, and mode!
And remember, range isn't just the biggest number, it's the difference between the biggest and smallest.

STEP 2

1. Problem 1
2. Problem 5
3. Problem 9

STEP 3

To find the mean, we add up all the numbers and then divide by how many numbers there are.
So, we have $24 + 31 + 12 + 38 + 12 + 15 = 132$ .
There are 6 numbers, so the mean is $132 \div 6 = 22$ .
The mean is 22!

STEP 4

For the median, we need to put the numbers in order.
That's $12, 12, 15, 24, 31, 38$ .
Since there are an even number of values, the median is the average of the two middle numbers.
Those are 15 and 24. $(15 + 24) \div 2 = 39 \div 2 = 19.5$ .
The median is 19.5!

STEP 5

The mode is the number that appears most often.
Here, 12 shows up twice, which is more than any other number.
So, the mode is 12!

STEP 6

The range is the difference between the largest and smallest numbers.
Our biggest number is 38 and our smallest is 12. $38 - 12 = 26$ .
The range is 26!

STEP 7

First, add all the numbers: $92 + 63 + 22 + 80 + 63 + 71 + 44 + 35 = 470$ .
There are 8 numbers, so $470 \div 8 = 58.75$ .
The mean is 58.75!

STEP 8

Let's order them: $22, 35, 44, 63, 63, 71, 80, 92$ .
We have an even number of values, so we average the two middle ones: $63$ and $63$ . $(63 + 63) \div 2 = 126 \div 2 = 63$ .
The median is 63!

STEP 9

The number 63 appears twice, more than any other number.
The mode is 63!

STEP 10

The largest number is 92 and the smallest is 22. $92 - 22 = 70$ .
The range is 70!

STEP 11

Add 'em up: $12 + 46 + 32 + 18 + 26 + 41 + 46 = 221$ .
There are 7 numbers, so $221 \div 7 = 31.57$ when rounded to two decimal places.
The mean is approximately 31.57!

STEP 12

In order: $12, 18, 26, 32, 41, 46, 46$ .
The middle number is 32.
The median is 32!

STEP 13

46 appears twice, which is more than any other number.
The mode is 46!

STEP 14

Largest is 46, smallest is 12. $46 - 12 = 34$ .
The range is 34!

STEP 15

Problem 1: Mean = 22, Median = 19.5, Mode = 12, Range = 26 Problem 5: Mean = 58.75, Median = 63, Mode = 63, Range = 70 Problem 9: Mean ≈ 31.57, Median = 32, Mode = 46, Range = 34

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Studdy Solution

STEP 1

What is this asking? We need to find the mean, median, mode, and range for a bunch of number sets. Watch out! Don't mix up mean, median, and mode!
And remember, range isn't just the biggest number, it's the difference between the biggest and smallest.

STEP 2

1. Problem 1
2. Problem 5
3. Problem 9

STEP 3

To find the mean, we add up all the numbers and then divide by how many numbers there are.
So, we have $24 + 31 + 12 + 38 + 12 + 15 = 132$ .
There are 6 numbers, so the mean is $132 \div 6 = 22$ .
The mean is 22!

STEP 4

For the median, we need to put the numbers in order.
That's $12, 12, 15, 24, 31, 38$ .
Since there are an even number of values, the median is the average of the two middle numbers.
Those are 15 and 24. $(15 + 24) \div 2 = 39 \div 2 = 19.5$ .
The median is 19.5!

STEP 5

The mode is the number that appears most often.
Here, 12 shows up twice, which is more than any other number.
So, the mode is 12!

STEP 6

The range is the difference between the largest and smallest numbers.
Our biggest number is 38 and our smallest is 12. $38 - 12 = 26$ .
The range is 26!

STEP 7

First, add all the numbers: $92 + 63 + 22 + 80 + 63 + 71 + 44 + 35 = 470$ .
There are 8 numbers, so $470 \div 8 = 58.75$ .
The mean is 58.75!

STEP 8

Let's order them: $22, 35, 44, 63, 63, 71, 80, 92$ .
We have an even number of values, so we average the two middle ones: $63$ and $63$ . $(63 + 63) \div 2 = 126 \div 2 = 63$ .
The median is 63!

STEP 9

The number 63 appears twice, more than any other number.
The mode is 63!

STEP 10

The largest number is 92 and the smallest is 22. $92 - 22 = 70$ .
The range is 70!

STEP 11

Add 'em up: $12 + 46 + 32 + 18 + 26 + 41 + 46 = 221$ .
There are 7 numbers, so $221 \div 7 = 31.57$ when rounded to two decimal places.
The mean is approximately 31.57!

STEP 12

In order: $12, 18, 26, 32, 41, 46, 46$ .
The middle number is 32.
The median is 32!

STEP 13

46 appears twice, which is more than any other number.
The mode is 46!

STEP 14

Largest is 46, smallest is 12. $46 - 12 = 34$ .
The range is 34!

STEP 15

Problem 1: Mean = 22, Median = 19.5, Mode = 12, Range = 26 Problem 5: Mean = 58.75, Median = 63, Mode = 63, Range = 70 Problem 9: Mean ≈ 31.57, Median = 32, Mode = 46, Range = 34

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Studdy Solution

STEP 1

What is this asking? We need to find the mean, median, mode, and range for a bunch of number sets. Watch out! Don't mix up mean, median, and mode!And remember, range isn't just the biggest number, it's the *difference* between the biggest and smallest.

STEP 2

1. Problem 12. Problem 53. Problem 9

STEP 3

To find the mean, we **add up** all the numbers and then **divide** by how many numbers there are.So, we have 24+31+12+38+12+15=13224 + 31 + 12 + 38 + 12 + 15 = 13224+31+12+38+12+15=132.There are **6** numbers, so the mean is 132÷6=22132 \div 6 = 22132÷6=22.The **mean is 22**!

STEP 4

STEP 5

The mode is the number that appears most often.Here, **12** shows up twice, which is more than any other number.So, the **mode is 12**!

STEP 6

The range is the difference between the largest and smallest numbers.Our biggest number is **38** and our smallest is **12**. 38−12=2638 - 12 = 2638−12=26.The **range is 26**!

STEP 7

First, add all the numbers: 92+63+22+80+63+71+44+35=47092 + 63 + 22 + 80 + 63 + 71 + 44 + 35 = 47092+63+22+80+63+71+44+35=470.There are **8** numbers, so 470÷8=58.75470 \div 8 = 58.75470÷8=58.75.The **mean is 58.75**!

STEP 8

Let's order them: 22,35,44,63,63,71,80,9222, 35, 44, 63, 63, 71, 80, 9222,35,44,63,63,71,80,92.We have an even number of values, so we average the two middle ones: 636363 and 636363. (63+63)÷2=126÷2=63(63 + 63) \div 2 = 126 \div 2 = 63(63+63)÷2=126÷2=63.The **median is 63**!

STEP 9

The number **63** appears twice, more than any other number.The **mode is 63**!

STEP 10

The largest number is **92** and the smallest is **22**. 92−22=7092 - 22 = 7092−22=70.The **range is 70**!

STEP 11

Add 'em up: 12+46+32+18+26+41+46=22112 + 46 + 32 + 18 + 26 + 41 + 46 = 22112+46+32+18+26+41+46=221.There are **7** numbers, so 221÷7=31.57221 \div 7 = 31.57221÷7=31.57 when rounded to two decimal places.The **mean is approximately 31.57**!

STEP 12

In order: 12,18,26,32,41,46,4612, 18, 26, 32, 41, 46, 4612,18,26,32,41,46,46.The middle number is **32**.The **median is 32**!

STEP 13

**46** appears twice, which is more than any other number.The **mode is 46**!

STEP 14

Largest is **46**, smallest is **12**. 46−12=3446 - 12 = 3446−12=34.The **range is 34**!

STEP 15

Problem 1: Mean = 22, Median = 19.5, Mode = 12, Range = 26 Problem 5: Mean = 58.75, Median = 63, Mode = 63, Range = 70 Problem 9: Mean ≈ 31.57, Median = 32, Mode = 46, Range = 34

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

What is this asking? We need to find the mean, median, mode, and range for a bunch of number sets. Watch out! Don't mix up mean, median, and mode!
And remember, range isn't just the biggest number, it's the difference between the biggest and smallest.

1. Problem 1
2. Problem 5
3. Problem 9

To find the mean, we add up all the numbers and then divide by how many numbers there are.
So, we have $24 + 31 + 12 + 38 + 12 + 15 = 132$ .
There are 6 numbers, so the mean is $132 \div 6 = 22$ .
The mean is 22!

The mode is the number that appears most often.
Here, 12 shows up twice, which is more than any other number.
So, the mode is 12!

The range is the difference between the largest and smallest numbers.
Our biggest number is 38 and our smallest is 12. $38 - 12 = 26$ .
The range is 26!

First, add all the numbers: $92 + 63 + 22 + 80 + 63 + 71 + 44 + 35 = 470$ .
There are 8 numbers, so $470 \div 8 = 58.75$ .
The mean is 58.75!

Let's order them: $22, 35, 44, 63, 63, 71, 80, 92$ .
We have an even number of values, so we average the two middle ones: $63$ and $63$ . $(63 + 63) \div 2 = 126 \div 2 = 63$ .
The median is 63!

The number 63 appears twice, more than any other number.
The mode is 63!

The largest number is 92 and the smallest is 22. $92 - 22 = 70$ .
The range is 70!

Add 'em up: $12 + 46 + 32 + 18 + 26 + 41 + 46 = 221$ .
There are 7 numbers, so $221 \div 7 = 31.57$ when rounded to two decimal places.
The mean is approximately 31.57!

In order: $12, 18, 26, 32, 41, 46, 46$ .
The middle number is 32.
The median is 32!

46 appears twice, which is more than any other number.
The mode is 46!

Largest is 46, smallest is 12. $46 - 12 = 34$ .
The range is 34!