Math  /  Algebra

QuestionMultiply. Assume that all variables represent positive real numbers. (cb)(c+b)(\sqrt{c}-b)(\sqrt{c}+b) (cb)(c+b)=(\sqrt{c}-b)(\sqrt{c}+b)= \square (Simplify your answer.)

Studdy Solution

STEP 1

1. We are multiplying two binomials.
2. The expression is in the form of a difference of squares.
3. All variables represent positive real numbers.

STEP 2

1. Recognize the pattern of the difference of squares.
2. Apply the difference of squares formula to simplify the expression.

STEP 3

Recognize that the expression (cb)(c+b)(\sqrt{c}-b)(\sqrt{c}+b) is in the form of a difference of squares, which is given by the formula:
(ab)(a+b)=a2b2 (a-b)(a+b) = a^2 - b^2
In this case, a=c a = \sqrt{c} and b=b b = b .

STEP 4

Apply the difference of squares formula:
(c)2b2 (\sqrt{c})^2 - b^2
Simplify the expression:
cb2 c - b^2
This is the simplified form of the expression.
The simplified expression is:
cb2 \boxed{c - b^2}

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