Math

QuestionНайдите n(B)n(B), если n(AB)=31n(A \cup B)=31, n(A)=18n(A)=18, n(AB)=9n(A \cap B)=9.

Studdy Solution

STEP 1

Assumptions1. The total number of elements in the union of sets A and B, denoted as n(AB)n(A \cup B), is31. . The total number of elements in set A, denoted as n(A)n(A), is18.
3. The total number of elements in the intersection of sets A and B, denoted as n(AB)n(A \cap B), is9.

STEP 2

We need to find the total number of elements in set B, denoted as n(B)n(B). We can use the formula for the number of elements in the union of two sets.
n(AB)=n(A)+n(B)n(AB)n(A \cup B) = n(A) + n(B) - n(A \cap B)

STEP 3

We can rearrange the formula to solve for n(B)n(B).
n(B)=n(AB)n(A)+n(AB)n(B) = n(A \cup B) - n(A) + n(A \cap B)

STEP 4

Now, plug in the given values for n(AB)n(A \cup B), n(A)n(A), and n(AB)n(A \cap B) to calculate n(B)n(B).
n(B)=3118+9n(B) =31 -18 +9

STEP 5

Calculate the total number of elements in set B.
n(B)=3118+9=22n(B) =31 -18 +9 =22The total number of elements in set B is22.

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