QuestionName the compounds and use Roman numerals if necessary. Spelling is important. 离 $\mathrm{CuO}$ : $\mathrm{Cu}_{2} \mathrm{O}$ : $\mathrm{CrS}$ : $\mathrm{Cr}_{2} \mathrm{~S}_{3}$

Studdy Solution

STEP 1

Assumptions1. The compounds areionic compounds. . The compounds are binary, meaning they are composed of two elements.
3. The compounds are named by stating the cation (positive ion) first, followed by the anion (negative ion).
4. If the metal in the compound can form ions with different charges, a Roman numeral indicating the charge is included in the name.
5. The names of the elements are Copper (Cu), Oxygen (), Chromium (Cr), andulfur ().

STEP 2

Let's start with the first compound, $\mathrm{Cu}$ . The cation is Cu (Copper) and the anion is O (xygen).

STEP 3

The anion (xygen) is named by taking the root of the element name and adding the suffix "-ide". So, Oxygen becomes Oxide.

STEP 4

Copper can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Copper must be +2, because Oxygen has a charge of -2 and the total charge of the compound must be zero.

STEP 5

So, the name of the compound $\mathrm{Cu}$ is Copper (II) Oxide.

STEP 6

Now, let's move on to the second compound, $\mathrm{Cu}_{2} \mathrm{}$ . The cation is Cu (Copper) and the anion is O (xygen).

STEP 7

Again, Oxygen becomes Oxide.

STEP 8

In this case, the charge on Copper must be +1, because Oxygen has a charge of -2 and there are two Copper atoms. So, the Roman numeral is I.

STEP 9

So, the name of the compound $\mathrm{Cu}_{2} \mathrm{}$ is Copper () Oxide.

STEP 10

Next, let's name the third compound, $\mathrm{Cr}$ . The cation is Cr (Chromium) and the anion is (ulfur).

STEP 11

The anion (ulfur) is named by taking the root of the element name and adding the suffix "-ide". So,ulfur becomesulfide.

STEP 12

Chromium can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Chromium must be +2, becauseulfur has a charge of -2 and the total charge of the compound must be zero.

STEP 13

So, the name of the compound $\mathrm{Cr}$ is Chromium (II)ulfide.

STEP 14

Finally, let's name the fourth compound, $\mathrm{Cr}_{2} \mathrm{~}_{3}$ . The cation is Cr (Chromium) and the anion is (ulfur).

STEP 15

Again,ulfur becomesulfide.

STEP 16

In this case, the charge on Chromium must be +3, becauseulfur has a charge of -2 and there are two Chromium atoms. So, the Roman numeral is III.

STEP 17

So, the name of the compound $\mathrm{Cr}_{2} \mathrm{~}_{3}$ is Chromium (III)ulfide.
The names of the compounds are $\mathrm{Cu}$ Copper (II) Oxide $\mathrm{Cu}_{2} \mathrm{}$ Copper () Oxide $\mathrm{Cr}$ Chromium (II)ulfide $\mathrm{Cr}_{2} \mathrm{~}_{3}$ Chromium (III)ulfide

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QuestionName the compounds and use Roman numerals if necessary. Spelling is important. 离 $\mathrm{CuO}$ : $\mathrm{Cu}_{2} \mathrm{O}$ : $\mathrm{CrS}$ : $\mathrm{Cr}_{2} \mathrm{~S}_{3}$

Studdy Solution

STEP 1

STEP 2

Let's start with the first compound, $\mathrm{Cu}$ . The cation is Cu (Copper) and the anion is O (xygen).

STEP 3

The anion (xygen) is named by taking the root of the element name and adding the suffix "-ide". So, Oxygen becomes Oxide.

STEP 4

Copper can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Copper must be +2, because Oxygen has a charge of -2 and the total charge of the compound must be zero.

STEP 5

So, the name of the compound $\mathrm{Cu}$ is Copper (II) Oxide.

STEP 6

Now, let's move on to the second compound, $\mathrm{Cu}_{2} \mathrm{}$ . The cation is Cu (Copper) and the anion is O (xygen).

STEP 7

Again, Oxygen becomes Oxide.

STEP 8

In this case, the charge on Copper must be +1, because Oxygen has a charge of -2 and there are two Copper atoms. So, the Roman numeral is I.

STEP 9

So, the name of the compound $\mathrm{Cu}_{2} \mathrm{}$ is Copper () Oxide.

STEP 10

Next, let's name the third compound, $\mathrm{Cr}$ . The cation is Cr (Chromium) and the anion is (ulfur).

STEP 11

The anion (ulfur) is named by taking the root of the element name and adding the suffix "-ide". So,ulfur becomesulfide.

STEP 12

Chromium can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Chromium must be +2, becauseulfur has a charge of -2 and the total charge of the compound must be zero.

STEP 13

So, the name of the compound $\mathrm{Cr}$ is Chromium (II)ulfide.

STEP 14

Finally, let's name the fourth compound, $\mathrm{Cr}_{2} \mathrm{~}_{3}$ . The cation is Cr (Chromium) and the anion is (ulfur).

STEP 15

Again,ulfur becomesulfide.

STEP 16

In this case, the charge on Chromium must be +3, becauseulfur has a charge of -2 and there are two Chromium atoms. So, the Roman numeral is III.

STEP 17

So, the name of the compound $\mathrm{Cr}_{2} \mathrm{~}_{3}$ is Chromium (III)ulfide.
The names of the compounds are $\mathrm{Cu}$ Copper (II) Oxide $\mathrm{Cu}_{2} \mathrm{}$ Copper () Oxide $\mathrm{Cr}$ Chromium (II)ulfide $\mathrm{Cr}_{2} \mathrm{~}_{3}$ Chromium (III)ulfide

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QuestionName the compounds and use Roman numerals if necessary. Spelling is important. 离 CuO\mathrm{CuO}CuO : Cu2O\mathrm{Cu}_{2} \mathrm{O}Cu2​O : CrS\mathrm{CrS}CrS : Cr2 S3\mathrm{Cr}_{2} \mathrm{~S}_{3}Cr2​ S3​

Studdy Solution

STEP 1

STEP 2

Let's start with the first compound, Cu\mathrm{Cu}Cu. The cation is Cu (Copper) and the anion is O (xygen).

STEP 3

The anion (xygen) is named by taking the root of the element name and adding the suffix "-ide". So, Oxygen becomes Oxide.

STEP 4

Copper can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Copper must be +2, because Oxygen has a charge of -2 and the total charge of the compound must be zero.

STEP 5

So, the name of the compound Cu\mathrm{Cu}Cu is Copper (II) Oxide.

STEP 6

Now, let's move on to the second compound, Cu2\mathrm{Cu}_{2} \mathrm{}Cu2​. The cation is Cu (Copper) and the anion is O (xygen).

STEP 7

Again, Oxygen becomes Oxide.

STEP 8

In this case, the charge on Copper must be +1, because Oxygen has a charge of -2 and there are two Copper atoms. So, the Roman numeral is I.

STEP 9

So, the name of the compound Cu2\mathrm{Cu}_{2} \mathrm{}Cu2​ is Copper () Oxide.

STEP 10

Next, let's name the third compound, Cr\mathrm{Cr}Cr. The cation is Cr (Chromium) and the anion is (ulfur).

STEP 11

The anion (ulfur) is named by taking the root of the element name and adding the suffix "-ide". So,ulfur becomesulfide.

STEP 12

Chromium can form ions with different charges, so we need to include a Roman numeral indicating the charge. In this case, the charge on Chromium must be +2, becauseulfur has a charge of -2 and the total charge of the compound must be zero.

STEP 13

So, the name of the compound Cr\mathrm{Cr}Cr is Chromium (II)ulfide.

STEP 14

Finally, let's name the fourth compound, Cr2 3\mathrm{Cr}_{2} \mathrm{~}_{3}Cr2​ 3​. The cation is Cr (Chromium) and the anion is (ulfur).

STEP 15

Again,ulfur becomesulfide.

STEP 16

In this case, the charge on Chromium must be +3, becauseulfur has a charge of -2 and there are two Chromium atoms. So, the Roman numeral is III.

STEP 17

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QuestionName the compounds and use Roman numerals if necessary. Spelling is important. 离 $\mathrm{CuO}$ : $\mathrm{Cu}_{2} \mathrm{O}$ : $\mathrm{CrS}$ : $\mathrm{Cr}_{2} \mathrm{~S}_{3}$

Let's start with the first compound, $\mathrm{Cu}$ . The cation is Cu (Copper) and the anion is O (xygen).

So, the name of the compound $\mathrm{Cu}$ is Copper (II) Oxide.

Now, let's move on to the second compound, $\mathrm{Cu}_{2} \mathrm{}$ . The cation is Cu (Copper) and the anion is O (xygen).

So, the name of the compound $\mathrm{Cu}_{2} \mathrm{}$ is Copper () Oxide.

Next, let's name the third compound, $\mathrm{Cr}$ . The cation is Cr (Chromium) and the anion is (ulfur).

So, the name of the compound $\mathrm{Cr}$ is Chromium (II)ulfide.

Finally, let's name the fourth compound, $\mathrm{Cr}_{2} \mathrm{~}_{3}$ . The cation is Cr (Chromium) and the anion is (ulfur).