Math

QuestionEvaluate: 8+(3+10)÷7-8+(3+-10) \div-7

Studdy Solution

STEP 1

Assumptions1. We will follow the order of operations, also known as BIDMAS or PEMAS, which stands for Brackets, Indices (or Exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).

STEP 2

First, we need to solve the expression inside the brackets.
8+(+10)÷7=8+(7)÷7-8+(+-10) \div-7 = -8+(-7) \div-7

STEP 3

Next, we perform the division operation.
8+(7)÷7=8+1-8+(-7) \div-7 = -8+1

STEP 4

Finally, we perform the addition operation.
8+1=7-8+1 = -7So, the expression 8+(3+10)÷7-8+(3+-10) \div-7 evaluates to -7.

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