Math

QuestionSolve the equation 2(2x+3)x1=I28-2(-2 x+3)-x-1=I-28.

Studdy Solution

STEP 1

Assumptions1. The equation is (x+3)x1=28-(- x+3)-x-1=-28 . The variable in the equation is xx
3. The equation is a linear equation4. The goal is to solve for xx

STEP 2

First, we need to simplify the equation. We can do this by distributing the 2-2 in the parentheses on the left side of the equation.
2(2x+)x1=28-2(-2 x+)-x-1=-28becomes4x6x1=I284x -6 - x -1 = I -28

STEP 3

Next, we combine like terms on the left side of the equation.
xx61=I28x - x -6 -1 = I -28becomes3x7=I283x -7 = I -28

STEP 4

Now, we need to isolate the variable xx on one side of the equation. We can do this by adding 77 to both sides of the equation.
3x7+7=I28+73x -7 +7 = I -28 +7becomes3x=I213x = I -21

STEP 5

Finally, we solve for xx by dividing both sides of the equation by 33.
3x3=213\frac{3x}{3} = \frac{ -21}{3}becomesx=213x = \frac{ -21}{3}So, the solution to the equation 2(2x+3)x1=28-2(-2 x+3)-x-1=-28 is x=213x = \frac{ -21}{3}.

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