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QuestionSolve the system of equations: −2x=1-2x = 1 and 4x−3y=04x - 3y = 0.

Studdy Solution

STEP 1

Assumptions1. We have two linear equations in two variables, x and y. . The equations are -x =1 and4x -3y =0

STEP 2

First, we need to solve the first equation for x. We can do this by dividing both sides of the equation by -2.
x=1−2x = \frac{1}{-2}

STEP 3

Now, plug in the value of -2 into the equation to calculate the value of x.
x=1−2=−0.5x = \frac{1}{-2} = -0.5

STEP 4

Now that we have the value of x, we can substitute it into the second equation to solve for y.4x−3y=04x -3y =0Substitute x = -0. into the equation.
4(−0.)−3y=04(-0.) -3y =0

STEP 5

implify the equation.
−2−3y=0-2 -3y =0

STEP 6

Now, we can solve for y by adding2 to both sides of the equation.
−3y=2-3y =2

STEP 7

Finally, we can find the value of y by dividing both sides of the equation by -3.
y=2−3y = \frac{2}{-3}

STEP 8

Now, plug in the value of -3 into the equation to calculate the value of y.
y=2−3=−23y = \frac{2}{-3} = -\frac{2}{3}The solution to the system of equations is x = -0.5 and y = -2/3.

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