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QuestionNuclear Chemistry - Nuclear Equations
1. Write a nuclear equation for the alpha decay of Protactinium - 232.
2. Write a nuclear equation for the beta decay of Radon - 168 .
3. Write a nuclear equation showing the fission of Nitrogen -15 into Lithium -6 and one other product.
4. Write a nuclear equation showing the fusion of Helium -4 and Lithium -7 resulting in one neutron and one other product.
5. Write a nuclear equation for the fission of Uranium - 238 that results in three neutrons, Krypton - 89 and on other product.

Studdy Solution

STEP 1

1. Alpha decay involves the emission of an alpha particle (α \alpha , or 24He ^4_2\text{He} ).
2. Beta decay involves the conversion of a neutron to a proton with the emission of a beta particle (β− \beta^- , or −10e ^0_{-1}\text{e} ).
3. Fission involves the splitting of a nucleus into smaller nuclei and possibly other particles.
4. Fusion involves the combining of nuclei to form a larger nucleus and possibly other particles.
5. The atomic number and mass number are conserved in nuclear reactions.

STEP 2

1. Write the nuclear equation for the alpha decay of Protactinium-232.
2. Write the nuclear equation for the beta decay of Radon-168.
3. Write the nuclear equation for the fission of Nitrogen-15.
4. Write the nuclear equation for the fusion of Helium-4 and Lithium-7.
5. Write the nuclear equation for the fission of Uranium-238.

STEP 3

Write the nuclear equation for the alpha decay of Protactinium-232:
Protactinium-232 (91232Pa ^{232}_{91}\text{Pa} ) undergoes alpha decay, emitting an alpha particle (24He ^4_2\text{He} ):
91232Pa→89228Ac+24He ^{232}_{91}\text{Pa} \rightarrow ^{228}_{89}\text{Ac} + ^4_2\text{He}

STEP 4

Write the nuclear equation for the beta decay of Radon-168:
Radon-168 (86168Rn ^{168}_{86}\text{Rn} ) undergoes beta decay, emitting a beta particle (−10e ^0_{-1}\text{e} ):
86168Rn→87168Fr+−10e ^{168}_{86}\text{Rn} \rightarrow ^{168}_{87}\text{Fr} + ^0_{-1}\text{e}

STEP 5

Write the nuclear equation for the fission of Nitrogen-15 into Lithium-6 and one other product:
Nitrogen-15 (715N ^{15}_{7}\text{N} ) fissions into Lithium-6 (36Li ^{6}_{3}\text{Li} ) and another product:
715N→36Li+49Be ^{15}_{7}\text{N} \rightarrow ^{6}_{3}\text{Li} + ^{9}_{4}\text{Be}

STEP 6

Write the nuclear equation for the fusion of Helium-4 and Lithium-7 resulting in one neutron and one other product:
Helium-4 (24He ^{4}_{2}\text{He} ) and Lithium-7 (37Li ^{7}_{3}\text{Li} ) fuse to form one neutron (01n ^1_0\text{n} ) and another product:
24He+37Li→510B+01n ^{4}_{2}\text{He} + ^{7}_{3}\text{Li} \rightarrow ^{10}_{5}\text{B} + ^1_0\text{n}

STEP 7

Write the nuclear equation for the fission of Uranium-238 that results in three neutrons, Krypton-89, and one other product:
Uranium-238 (92238U ^{238}_{92}\text{U} ) fissions into Krypton-89 (3689Kr ^{89}_{36}\text{Kr} ), three neutrons (3×01n 3 \times ^1_0\text{n} ), and another product:
92238U→3689Kr+56146Ba+3×01n ^{238}_{92}\text{U} \rightarrow ^{89}_{36}\text{Kr} + ^{146}_{56}\text{Ba} + 3 \times ^1_0\text{n}

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