QuestionIn a chemistry test, 18 out of 49 students got Bs. What percent is this? Round to the nearest whole number.

Studdy Solution

STEP 1

Assumptions1. The number of students who got As is12. The number of students who got Bs is183. The number of students who got Cs is194. We are asked to find the percent of students who received Bs

STEP 2

First, we need to find the total number of students. We can do this by adding the number of students who got As, Bs, and Cs.
$Total\, students = Number\, of\, As + Number\, of\, Bs + Number\, of\, Cs$

STEP 3

Now, plug in the given values for the number of As, Bs, and Cs to calculate the total number of students.
$Total\, students =12 +18 +19$

STEP 4

Calculate the total number of students.
$Total\, students =12 +18 +19 =49$

STEP 5

Now that we have the total number of students, we can find the percent of students who received Bs. This can be done by dividing the number of Bs by the total number of students and then multiplying by100.
$Percent\, of\, Bs = (Number\, of\, Bs / Total\, students) \\times100$

STEP 6

Plug in the values for the number of Bs and the total number of students to calculate the percent of Bs.
$Percent\, of\, Bs = (18 /49) \\times100$

STEP 7

Calculate the percent of students who received Bs.
$Percent\, of\, Bs = (18 /49) \\times100 \approx36.73\%$

STEP 8

Round the answer to the ones place.
$Percent\, of\, Bs \approx37\%$ The percent of students who received Bs is approximately37%.

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