Math

QuestionIn a class of 49 students, 17 got Bs and 19 got Cs. Find the percent of students with Bs and Cs to the nearest whole number.

Studdy Solution

STEP 1

Assumptions1. The number of students who got As is13. The number of students who got Bs is173. The number of students who got Cs is194. We are asked to find the percentage of students who received Bs and Cs separately5. The total number of students is the sum of the students who got As, Bs, and Cs

STEP 2

First, we need to find the total number of students. We can do this by adding the number of students who got As, Bs, and Cs.
Totalstudents=StudentswithAs+StudentswithBs+StudentswithCsTotal\, students = Students\, with\, As + Students\, with\, Bs + Students\, with\, Cs

STEP 3

Now, plug in the given values for the number of students who got As, Bs, and Cs to calculate the total number of students.
Totalstudents=13+17+19Total\, students =13 +17 +19

STEP 4

Calculate the total number of students.
Totalstudents=13+17+19=49Total\, students =13 +17 +19 =49

STEP 5

Now that we have the total number of students, we can find the percentage of students who received Bs. This can be done by dividing the number of students who got Bs by the total number of students and then multiplying by100.
PercentageofBs=(StudentswithBs/Totalstudents)times100%Percentage\, of\, Bs = (Students\, with\, Bs / Total\, students) \\times100\%

STEP 6

Plug in the values for the number of students who got Bs and the total number of students to calculate the percentage of students who received Bs.
PercentageofBs=(17/49)times100%Percentage\, of\, Bs = (17 /49) \\times100\%

STEP 7

Calculate the percentage of students who received Bs.
PercentageofBs=(17/49)times100%=34.7%Percentage\, of\, Bs = (17 /49) \\times100\% =34.7\%

STEP 8

Round the percentage to the ones place.
PercentageofBs=35%Percentage\, of\, Bs =35\%Part A35% of the students received Bs.

STEP 9

Similarly, we can find the percentage of students who received Cs. This can be done by dividing the number of students who got Cs by the total number of students and then multiplying by100.
PercentageofCs=(StudentswithCs/Totalstudents)times100%Percentage\, of\, Cs = (Students\, with\, Cs / Total\, students) \\times100\%

STEP 10

Plug in the values for the number of students who got Cs and the total number of students to calculate the percentage of students who received Cs.
PercentageofCs=(19/49)times100%Percentage\, of\, Cs = (19 /49) \\times100\%

STEP 11

Calculate the percentage of students who received Cs.
PercentageofCs=(19/49)times100%=38.8%Percentage\, of\, Cs = (19 /49) \\times100\% =38.8\%

STEP 12

Round the percentage to the ones place.
PercentageofCs=39%Percentage\, of\, Cs =39\%Part B39% of the students received Cs.

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