QuestionSolve for $x$ : $\frac{1}{3} x + 3 = \frac{14}{3}$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $\frac{1}{3} x+3=\frac{14}{3}$ . . We are solving for $x$ .

STEP 2

We start by isolating the term with $x$ on one side of the equation. We can do this by subtracting from both sides of the equation.
$\frac{1}{} x+-=\frac{14}{}-$

STEP 3

implify the equation.
$\frac{1}{3} x=\frac{14}{3}-3$

STEP 4

Convert the3 on the right side of the equation to a fraction with3 as the denominator, so we can subtract it from $\frac{14}{3}$ .
$3 = \frac{9}{3}$ So, the equation becomes $\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}$

STEP 5

Subtract the fractions on the right side of the equation.
$\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}=\frac{5}{3}$

STEP 6

To solve for $x$ , we need to get rid of the $\frac{1}{3}$ coefficient. We can do this by multiplying both sides of the equation by3.
$3 \times \frac{1}{3} x=3 \times \frac{5}{3}$

STEP 7

implify the equation to find the value of $x$ .
$x=3 \times \frac{5}{3}=5$ So, the solution to the equation is $x=5$ .

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QuestionSolve for $x$ : $\frac{1}{3} x + 3 = \frac{14}{3}$ .

Studdy Solution

STEP 1

Assumptions1. The equation is $\frac{1}{3} x+3=\frac{14}{3}$ . . We are solving for $x$ .

STEP 2

We start by isolating the term with $x$ on one side of the equation. We can do this by subtracting from both sides of the equation.
$\frac{1}{} x+-=\frac{14}{}-$

STEP 3

implify the equation.
$\frac{1}{3} x=\frac{14}{3}-3$

STEP 4

Convert the3 on the right side of the equation to a fraction with3 as the denominator, so we can subtract it from $\frac{14}{3}$ .
$3 = \frac{9}{3}$ So, the equation becomes $\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}$

STEP 5

Subtract the fractions on the right side of the equation.
$\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}=\frac{5}{3}$

STEP 6

To solve for $x$ , we need to get rid of the $\frac{1}{3}$ coefficient. We can do this by multiplying both sides of the equation by3.
$3 \times \frac{1}{3} x=3 \times \frac{5}{3}$

STEP 7

implify the equation to find the value of $x$ .
$x=3 \times \frac{5}{3}=5$ So, the solution to the equation is $x=5$ .

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QuestionSolve for xxx: 13x+3=143\frac{1}{3} x + 3 = \frac{14}{3}31​x+3=314​.

Studdy Solution

STEP 1

Assumptions1. The equation is 13x+3=143\frac{1}{3} x+3=\frac{14}{3}31​x+3=314​. . We are solving for xxx.

STEP 2

We start by isolating the term with xxx on one side of the equation. We can do this by subtracting from both sides of the equation.1x+−=14−\frac{1}{} x+-=\frac{14}{}-1​x+−=14​−

STEP 3

implify the equation.13x=143−3\frac{1}{3} x=\frac{14}{3}-331​x=314​−3

STEP 4

Convert the3 on the right side of the equation to a fraction with3 as the denominator, so we can subtract it from 143\frac{14}{3}314​.3=933 = \frac{9}{3}3=39​So, the equation becomes13x=143−93\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}31​x=314​−39​

STEP 5

Subtract the fractions on the right side of the equation.13x=143−93=53\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}=\frac{5}{3}31​x=314​−39​=35​

STEP 6

To solve for xxx, we need to get rid of the 13\frac{1}{3}31​ coefficient. We can do this by multiplying both sides of the equation by3.3×13x=3×533 \times \frac{1}{3} x=3 \times \frac{5}{3}3×31​x=3×35​

STEP 7

implify the equation to find the value of xxx.x=3×53=5x=3 \times \frac{5}{3}=5x=3×35​=5So, the solution to the equation is x=5x=5x=5.

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QuestionSolve for $x$ : $\frac{1}{3} x + 3 = \frac{14}{3}$ .

Assumptions1. The equation is $\frac{1}{3} x+3=\frac{14}{3}$ . . We are solving for $x$ .

We start by isolating the term with $x$ on one side of the equation. We can do this by subtracting from both sides of the equation.
$\frac{1}{} x+-=\frac{14}{}-$

implify the equation.
$\frac{1}{3} x=\frac{14}{3}-3$

Convert the3 on the right side of the equation to a fraction with3 as the denominator, so we can subtract it from $\frac{14}{3}$ .
$3 = \frac{9}{3}$ So, the equation becomes $\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}$

Subtract the fractions on the right side of the equation.
$\frac{1}{3} x=\frac{14}{3}-\frac{9}{3}=\frac{5}{3}$

To solve for $x$ , we need to get rid of the $\frac{1}{3}$ coefficient. We can do this by multiplying both sides of the equation by3.
$3 \times \frac{1}{3} x=3 \times \frac{5}{3}$

implify the equation to find the value of $x$ .
$x=3 \times \frac{5}{3}=5$ So, the solution to the equation is $x=5$ .