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Math

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PROBLEM

Beregn arealet af trekanter med g og h: a) g=3, h=4; b) g=2, h=4; c) g=8, h=4; d) g=10, h=2. Beregn cirkelareal med π=3\pi=3.

STEP 1

Assumptions1. The area of a triangle is given by the formula A=1ghA = \frac{1}{}gh, where gg is the base and hh is the height.
. The base and height of the triangles are given in the problem.
3. The area of a circle is given by the formula A = \pi r^, where rr is the radius and π\pi is approximately3.14159, but in this problem, we are told to use π=3\pi =3.

STEP 2

First, let's calculate the area of the first triangle. We can do this by plugging the given values for the base and height into the formula for the area of a triangle.
A=12ghA = \frac{1}{2}gh

STEP 3

Now, plug in the given values for the base and height to calculate the area of the first triangle.
A=12×3×A = \frac{1}{2} \times3 \times

STEP 4

Calculate the area of the first triangle.
A=12×3×4=6A = \frac{1}{2} \times3 \times4 =6

STEP 5

Repeat steps2-4 for the remaining triangles, plugging in the given values for the base and height for each triangle.
For the second triangleA=12×2×4=4A = \frac{1}{2} \times2 \times4 =4For the third triangleA=12×8×4=16A = \frac{1}{2} \times8 \times4 =16For the fourth triangleA=12×10×2=10A = \frac{1}{2} \times10 \times2 =10

SOLUTION

The areas of the triangles are as followsa)6b)4c)16d)10

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