QuestionFind the value of $x$ in $g = x \sqrt{p}$ if $p = \frac{2 g^{2}}{50}$ .

Studdy Solution

STEP 1

Assumptions1. The formula for estimating the likelihood of scoring $1500+$ on the SAT is given by $p=\frac{ g^{}}{50}$ , where $g$ is the student's average GPA by their junior year. . The formula can also be written in the form of $g=x \sqrt{p}$ , where $x$ is a constant.

STEP 2

We are asked to find the value of $x$ , so we need to express $g$ in terms of $p$ and $x$ using the given formula.We start by rearranging the given formula to solve for $g$ $g=\sqrt{\frac{p \times50}{2}}$

STEP 3

Now, we compare this with the form $g=x \sqrt{p}$ to find the value of $x$ .From the rearranged formula, we can see that $x$ is equal to the square root of $\frac{50}{2}$ .
$x=\sqrt{\frac{50}{2}}$

STEP 4

Now, calculate the value of $x$ .
$x=\sqrt{\frac{50}{2}}=\sqrt{25}=$ So, the value of $x$ is $$.

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