Math

QuestionA company buys a robot for \$87,000. Analyze its 8-year depreciation data and answer the following:
a. Identify the function type and write a linear function for value VV over time tt. b. Graph the function and explain straight line depreciation. c. Interpret the slope and intercepts. d. Find a real-life example of straight line depreciation, model it, and graph it.

Studdy Solution

STEP 1

Assumptions1. The initial value of the robot is $87,000. The value of the robot depreciates linearly over an8-year period3. The value of the robot at the end of each year is given in the table

STEP 2

First, we need to determine the type of function that represents the data. By observing the table, we can see that the value of the robot decreases by a constant amount each year. This suggests that the function is a linear function.

STEP 3

To write a linear function, we need to find the slope and the y-intercept. The slope is the rate of change, which is the change in the value of the robot divided by the change in time.
lope=ChangeinvalueChangeintimelope = \frac{Change\, in\, value}{Change\, in\, time}

STEP 4

We can calculate the slope using the values from the first two years.
lope=$79,750$87,00010lope = \frac{\$79,750 - \$87,000}{1 -0}

STEP 5

Calculate the slope.
lope=$7,2501=$7,250lope = \frac{-\$7,250}{1} = -\$7,250

STEP 6

The y-intercept is the value of the robot at time0, which is $87,000.

STEP 7

Now we can write the linear function. The general form of a linear function is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.
V(t)=$7,250t+$87,000V(t) = -\$7,250t + \$87,000

STEP 8

To sketch a graph of the function, plot the initial value at time0 and use the slope to determine the value at each subsequent year. The graph will be a straight line that decreases from left to right, which is why this type of depreciation is called straight line depreciation.

STEP 9

The slope of the graph, -\$7,250, represents the amount the value of the robot decreases each year. The y-intercept, \$87,000, represents the initial value of the robot.

STEP 10

For part d, an example of straight line depreciation could be a car that was purchased for \20,000anddepreciatesby$2,000eachyear.Thefunctionthatmodelsthisexamplewouldbe20,000 and depreciates by \$2,000 each year. The function that models this example would beV(t)=$2,000t+$20,000V(t) = -\$2,000t + \$20,000$The graph of this function would be a straight line that starts at \$20,000 and decreases by \$2,000 each year.

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