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Math

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PROBLEM

Perform the elementary row operation 13R2R2\frac{1}{3} R_{2} \rightarrow R_{2} on the given matrix.
[132693]\left[\begin{array}{cc:c} 1 & 3 & 2 \\ -6 & 9 & 3 \end{array}\right] Resulting matrix:
\square
\square
\square
\square
\square
\square

STEP 1

1. We are given a matrix and need to perform a specific elementary row operation.
2. The operation 13R2R2\frac{1}{3} R_{2} \rightarrow R_{2} means to multiply every element in the second row by 13\frac{1}{3}.
3. The matrix is a 2×32 \times 3 matrix, with the second row being [6,9,3][-6, 9, 3].

STEP 2

1. Identify the elements in the second row.
2. Apply the row operation to each element in the second row.
3. Write the resulting matrix after the operation.

STEP 3

Identify the elements in the second row of the matrix:
The second row is [6,9,3][-6, 9, 3].

STEP 4

Apply the row operation 13R2R2\frac{1}{3} R_{2} \rightarrow R_{2} to each element in the second row:
- Multiply 6-6 by 13\frac{1}{3}:
$$ -6 \times \frac{1}{3} = -2
\] - Multiply 99 by 13\frac{1}{3}:
$$ 9 \times \frac{1}{3} = 3
\] - Multiply 33 by 13\frac{1}{3}:
$$ 3 \times \frac{1}{3} = 1
\]

SOLUTION

Write the resulting matrix after performing the operation:
The first row remains unchanged: [1,3,2][1, 3, 2].
The new second row is: [2,3,1][-2, 3, 1].
Thus, the resulting matrix is:
[132231]\left[\begin{array}{cc:c} 1 & 3 & 2 \\ -2 & 3 & 1 \end{array}\right] The resulting matrix is:
[132231]\left[\begin{array}{cc:c} 1 & 3 & 2 \\ -2 & 3 & 1 \end{array}\right]

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