Math

QuestionCalculate the pH\mathrm{pH} for [H3O+]=5.79×104M\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=5.79 \times 10^{-4} \mathrm{M}.

Studdy Solution

STEP 1

Assumptions1. The concentration of H3+\mathrm{H}_{3} \mathrm{}^{+} is given as 5.79×104M5.79 \times10^{-4} M . The formula to calculate pH is log10[H3+]-\log{10}\left[\mathrm{H}_{3} \mathrm{}^{+}\right]

STEP 2

Plug in the given value for the concentration of H+\mathrm{H}_{} \mathrm{}^{+} into the formula to calculate pH.
pH=log10[5.79×104]\mathrm{pH}=-\log{10}\left[5.79 \times10^{-4}\right]

STEP 3

Calculate the pH value.
The pH value is calculated by taking the negative logarithm (base10) of the hydronium ion concentration.pH=log10(5.79×10)\mathrm{pH} = -\log{10}(5.79 \times10^{-})

STEP 4

The pH value is approximately3.24 when rounded to two decimal places.
The solution to this problem is pH=3.24\mathrm{pH} =3.24.

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