Math  /  Calculus

QuestionPoints: 0 of 1 a. limx2g(x)\lim _{x \rightarrow 2} g(x) b. limx3g(x)\lim _{x \rightarrow 3} g(x) c. limx4g(x)\lim _{x \rightarrow 4} g(x) d. limx3.5g(x)\lim _{x \rightarrow 3.5} g(x) a. What is limx2g(x)\lim _{x \rightarrow 2} g(x) ? Choose the correct answer below and, if necessary, if in the arswer box to complete your choice A. limx2g(x)=\lim _{x \rightarrow 2} g(x)= \square B. limx2g(x)\lim _{x \rightarrow 2} g(x) does not exist

Studdy Solution

STEP 1

1. The function g(x) g(x) is defined by the graph provided.
2. The limit limxag(x) \lim_{{x \to a}} g(x) exists if and only if both the left-hand limit limxag(x) \lim_{{x \to a^-}} g(x) and the right-hand limit limxa+g(x) \lim_{{x \to a^+}} g(x) exist and are equal.

STEP 2

1. Determine the left-hand limit limx2g(x) \lim_{{x \to 2^-}} g(x) .
2. Determine the right-hand limit limx2+g(x) \lim_{{x \to 2^+}} g(x) .
3. Compare the left-hand limit and the right-hand limit to conclude if the two-sided limit limx2g(x) \lim_{{x \to 2}} g(x) exists.

STEP 3

Examine the graph as x x approaches 2 from the left to find limx2g(x) \lim_{{x \to 2^-}} g(x) .
The graph shows a line segment from (0,2) (0, -2) to (2,4) (2, 4) , indicating that as x x approaches 2 from the left, g(x) g(x) approaches 4. limx2g(x)=4 \lim_{{x \to 2^-}} g(x) = 4

STEP 4

Examine the graph as x x approaches 2 from the right to find limx2+g(x) \lim_{{x \to 2^+}} g(x) .
The graph shows a point at (2,4) (2, 4) and a line segment starting from (2,4) (2, 4) to (3,1) (3, 1) . Therefore, as x x approaches 2 from the right, g(x) g(x) also approaches 4. limx2+g(x)=4 \lim_{{x \to 2^+}} g(x) = 4

STEP 5

Compare the left-hand limit and the right-hand limit to conclude the two-sided limit limx2g(x) \lim_{{x \to 2}} g(x) .
Since both limx2g(x) \lim_{{x \to 2^-}} g(x) and limx2+g(x) \lim_{{x \to 2^+}} g(x) are equal to 4: limx2g(x)=4 \lim_{{x \to 2}} g(x) = 4
Solution: The correct answer is limx2g(x)=4 \lim_{{x \to 2}} g(x) = 4

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