Math  /  Geometry

QuestionPoints P,Q,RP, Q, R and SS have position vectors p=(63),q=(35),r=(13)\mathbf{p}=\binom{6}{3}, \mathbf{q}=\binom{-3}{-5}, \mathbf{r}=\binom{1}{-3} and s=(105)\mathbf{s}=\binom{10}{5} Prove that the quadrilateral PQRSP Q R S is a parallelogram.

Studdy Solution

STEP 1

1. The position vectors of points P,Q,R, P, Q, R, and S S are given.
2. A quadrilateral is a parallelogram if opposite sides are equal in length and parallel.

STEP 2

1. Calculate the vectors representing the sides of the quadrilateral.
2. Show that opposite sides are equal in length.
3. Show that opposite sides are parallel.

STEP 3

Calculate the vectors representing the sides of the quadrilateral:
PQundefined=qp=(35)(63)=(3653)=(98)\overrightarrow{PQ} = \mathbf{q} - \mathbf{p} = \binom{-3}{-5} - \binom{6}{3} = \binom{-3 - 6}{-5 - 3} = \binom{-9}{-8}
QRundefined=rq=(13)(35)=(1+33+5)=(42)\overrightarrow{QR} = \mathbf{r} - \mathbf{q} = \binom{1}{-3} - \binom{-3}{-5} = \binom{1 + 3}{-3 + 5} = \binom{4}{2}
RSundefined=sr=(105)(13)=(1015+3)=(98)\overrightarrow{RS} = \mathbf{s} - \mathbf{r} = \binom{10}{5} - \binom{1}{-3} = \binom{10 - 1}{5 + 3} = \binom{9}{8}
SPundefined=ps=(63)(105)=(61035)=(42)\overrightarrow{SP} = \mathbf{p} - \mathbf{s} = \binom{6}{3} - \binom{10}{5} = \binom{6 - 10}{3 - 5} = \binom{-4}{-2}

STEP 4

Show that opposite sides are equal in length:
Calculate the magnitudes:
PQundefined=(9)2+(8)2=81+64=145|\overrightarrow{PQ}| = \sqrt{(-9)^2 + (-8)^2} = \sqrt{81 + 64} = \sqrt{145}
RSundefined=92+82=81+64=145|\overrightarrow{RS}| = \sqrt{9^2 + 8^2} = \sqrt{81 + 64} = \sqrt{145}
QRundefined=42+22=16+4=20|\overrightarrow{QR}| = \sqrt{4^2 + 2^2} = \sqrt{16 + 4} = \sqrt{20}
SPundefined=(4)2+(2)2=16+4=20|\overrightarrow{SP}| = \sqrt{(-4)^2 + (-2)^2} = \sqrt{16 + 4} = \sqrt{20}
Since PQundefined=RSundefined |\overrightarrow{PQ}| = |\overrightarrow{RS}| and QRundefined=SPundefined |\overrightarrow{QR}| = |\overrightarrow{SP}| , opposite sides are equal.

STEP 5

Show that opposite sides are parallel:
Check if vectors are scalar multiples:
PQundefined=(98),RSundefined=(98)\overrightarrow{PQ} = \binom{-9}{-8}, \quad \overrightarrow{RS} = \binom{9}{8}
PQundefined=1×RSundefined\overrightarrow{PQ} = -1 \times \overrightarrow{RS}
QRundefined=(42),SPundefined=(42)\overrightarrow{QR} = \binom{4}{2}, \quad \overrightarrow{SP} = \binom{-4}{-2}
QRundefined=1×SPundefined\overrightarrow{QR} = -1 \times \overrightarrow{SP}
Since PQundefined \overrightarrow{PQ} is parallel to RSundefined \overrightarrow{RS} and QRundefined \overrightarrow{QR} is parallel to SPundefined \overrightarrow{SP} , opposite sides are parallel.
Thus, the quadrilateral PQRS PQRS is a parallelogram.

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