Math  /  Calculus

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DETAILS MY NOTES TANAPMATH7 3.3.005. PRACTICE ANOTHER population (in billions) as a function of time tt (in years), with t=0t=0 corresponding to the beginning of 1990. (Round your answers to two decimal places.) (a) If the world population continues to grow at approximately 2%/year2 \% / y e a r, find the length of time t4t_{4} (in yr) required for the population to quadruple in size. t4=t_{4}= \square yr (b) Using the time t4t_{4} found in part (a), what would be the world population (in billions of people) if the growth rate were reduced to 1.7%/yr1.7 \% / y r ? \square billion people Need Help? Read it Watch it

Studdy Solution

STEP 1

1. The population grows exponentially.
2. The initial population size is P0 P_0 .
3. The growth rate is 2% 2\% per year for part (a) and 1.7% 1.7\% per year for part (b).

STEP 2

1. Determine the formula for exponential growth.
2. Calculate the time required for the population to quadruple.
3. Calculate the population size with a reduced growth rate.

STEP 3

Recall the formula for exponential growth:
P(t)=P0ert P(t) = P_0 \cdot e^{rt}
where P(t) P(t) is the population at time t t , P0 P_0 is the initial population, r r is the growth rate, and t t is the time in years.

STEP 4

To find the time t4 t_4 required for the population to quadruple, set P(t4)=4P0 P(t_4) = 4P_0 and solve for t4 t_4 :
4P0=P0e0.02t4 4P_0 = P_0 \cdot e^{0.02t_4}
Divide both sides by P0 P_0 :
4=e0.02t4 4 = e^{0.02t_4}
Take the natural logarithm of both sides:
ln(4)=0.02t4 \ln(4) = 0.02t_4
Solve for t4 t_4 :
t4=ln(4)0.02 t_4 = \frac{\ln(4)}{0.02}
Calculate t4 t_4 and round to two decimal places:
t41.38630.0269.32 years t_4 \approx \frac{1.3863}{0.02} \approx 69.32 \text{ years}

STEP 5

Using the time t469.32 t_4 \approx 69.32 years, calculate the population if the growth rate is reduced to 1.7% 1.7\% :
P(t4)=P0e0.017×69.32 P(t_4) = P_0 \cdot e^{0.017 \times 69.32}
Calculate the exponent:
0.017×69.321.17844 0.017 \times 69.32 \approx 1.17844
Calculate P(t4) P(t_4) :
P(t4)=P0e1.17844 P(t_4) = P_0 \cdot e^{1.17844}
P(t4)P03.25 P(t_4) \approx P_0 \cdot 3.25
The population would be approximately 3.25 3.25 times the initial population, in billions.
The time required for the population to quadruple is:
69.32 years \boxed{69.32} \text{ years}
The population with a reduced growth rate would be approximately:
3.25 billion people \boxed{3.25} \text{ billion people}

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