Math  /  Data & Statistics

QuestionPractice Exercises 1) Which of the following are valid probability distributions? Explain a) \begin{tabular}{|c|c|} \hline x\boldsymbol{x} & P(x)\boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.5 \\ \hline 1 & 0.25 \\ \hline 2 & 0.25 \\ \hline \end{tabular} b) \begin{tabular}{|c|c|} \hline x\boldsymbol{x} & P(x)\boldsymbol{P}(\boldsymbol{x}) \\ \hline 0.5 & 0.2 \\ \hline 0.2 & 0.3 \\ \hline 0.3 & 0.25 \\ \hline \end{tabular} c) \begin{tabular}{|c|c|} \hline x\boldsymbol{x} & P(x)\boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.3 \\ \hline 1 & 0.25 \\ \hline 2 & 0.25 \\ \hline 3 & 0.2 \\ \hline \end{tabular}

Studdy Solution

STEP 1

1. A valid probability distribution must satisfy two conditions: - All probabilities P(x) P(x) must be non-negative. - The sum of all probabilities P(x) P(x) must equal 1.

STEP 2

1. Verify non-negativity of probabilities for each distribution.
2. Verify that the sum of probabilities equals 1 for each distribution.

STEP 3

For distribution (a), list the probabilities:
P(x)={0.5,0.2,0.3} P(x) = \{0.5, 0.2, 0.3\}
Verify non-negativity:
All probabilities are non-negative.

STEP 4

For distribution (a), calculate the sum of probabilities:
0.5+0.2+0.3=1.0 0.5 + 0.2 + 0.3 = 1.0
The sum is 1, so distribution (a) is valid.

STEP 5

For distribution (b), list the probabilities:
P(x)={0,0.5,0.5} P(x) = \{0, 0.5, 0.5\}
Verify non-negativity:
All probabilities are non-negative.

STEP 6

For distribution (b), calculate the sum of probabilities:
0+0.5+0.5=1.0 0 + 0.5 + 0.5 = 1.0
The sum is 1, so distribution (b) is valid.

STEP 7

For distribution (c), list the probabilities:
P(x)={0.25,0.25,0.3,0.2} P(x) = \{0.25, 0.25, 0.3, 0.2\}
Verify non-negativity:
All probabilities are non-negative.

STEP 8

For distribution (c), calculate the sum of probabilities:
0.25+0.25+0.3+0.2=1.0 0.25 + 0.25 + 0.3 + 0.2 = 1.0
The sum is 1, so distribution (c) is valid.
All distributions (a), (b), and (c) are valid probability distributions.

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