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PROBLEM

Problem 8. An e.m.f. of 250 V is connected across a resistance and the current flowing through the resistance is 4 A . What is the power developed? Ans. 1 kW.

STEP 1

1. The electromotive force (e.m.f) is 250 volts (V).
2. The current flowing through the resistance is 4 amperes (A).
3. We need to find the power developed in the circuit.
4. Power can be calculated using the formula P=VI P = VI , where P P is power, V V is voltage, and I I is current.

STEP 2

1. Identify the known values and the formula needed.
2. Substitute the known values into the formula.
3. Calculate the power.
4. Convert the power into kilowatts if necessary.

STEP 3

Identify the known values and the formula needed.
- Known values:
- Voltage (V V ) = 250 V
- Current (I I ) = 4 A
- Formula for power (P P ):
P=VI P = VI

STEP 4

Substitute the known values into the formula.
P=250V×4A P = 250 \, \text{V} \times 4 \, \text{A}

STEP 5

Calculate the power.
P=250×4=1000W P = 250 \times 4 = 1000 \, \text{W}

SOLUTION

Convert the power into kilowatts if necessary.
Since 1kW=1000W 1 \, \text{kW} = 1000 \, \text{W} , we have:
P=1000W=1kW P = 1000 \, \text{W} = 1 \, \text{kW} The power developed is:
1kW \boxed{1 \, \text{kW}}

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