Math  /  Algebra

QuestionQuestion 10 (3 points)
4. A coffee shop sells pastries for $3\$ 3 each. The following aquation modelas the total revenue for the day f(x)f(x) (if dollary) from solling xx pastries. Round all answers to the nearest hundredth, if necessary. 1(x)=3x201(x)=3 x-20 b. How many pastries would need to be sold to make $436\$ 436 revenue? (3 points) \square \square

Studdy Solution

STEP 1

1. The coffee shop sells each pastry for \$3.
2. The function \( f(x) = 3x - 20 \) models the total revenue in dollars from selling \( x \) pastries.
3. We need to find the number of pastries \( x \) that need to be sold to make \$436 in revenue.
4. Answers should be rounded to the nearest hundredth if necessary.

STEP 2

1. Understand the given function.
2. Set up the equation to find x x .
3. Solve the equation for x x .
4. Round the answer to the nearest hundredth if necessary.

STEP 3

Understand the given function f(x)=3x20 f(x) = 3x - 20 .
This function represents the total revenue from selling x x pastries, where each pastry contributes \$3 to the revenue, and there is a constant subtraction of \$20.

STEP 4

Set up the equation to find x x .
We want the revenue to be \$436, so set \( f(x) = 436 \).
3x20=436 3x - 20 = 436

STEP 5

Solve the equation for x x .
First, add 20 to both sides of the equation to isolate the term with x x :
3x20+20=436+20 3x - 20 + 20 = 436 + 20 3x=456 3x = 456
Next, divide both sides by 3 to solve for x x :
x=4563 x = \frac{456}{3} x=152 x = 152

STEP 6

Round the answer to the nearest hundredth if necessary.
Since x=152 x = 152 is already a whole number, no rounding is necessary.
The number of pastries that need to be sold to make \$436 in revenue is:
152 \boxed{152}

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