QuestionQuestion 2 (2 points) What is the daughter nuclide when Bi -214 experiences beta decay? (Write your answer as a symbol-mass number) A
Studdy Solution
STEP 1
1. Beta decay involves the transformation of a neutron into a proton, with the emission of a beta particle (an electron) and an antineutrino.
2. The atomic number of the element increases by 1, while the mass number remains unchanged.
STEP 2
1. Identify the initial nuclide.
2. Apply the beta decay transformation.
3. Determine the daughter nuclide.
STEP 3
Identify the initial nuclide:
The initial nuclide is Bismuth-214, denoted as .
STEP 4
Apply the beta decay transformation:
In beta decay, a neutron in the nucleus is converted into a proton, increasing the atomic number by 1. The mass number remains the same.
STEP 5
Determine the daughter nuclide:
- The atomic number of Bismuth (Bi) is 83. After beta decay, the atomic number increases to 84.
- The element with atomic number 84 is Polonium (Po).
- The mass number remains 214.
Thus, the daughter nuclide is .
The daughter nuclide is:
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