Math  /  Discrete

QuestionQuestion 7 (1 point) Consider the following sets: A={1,2,3,4,5,6,7,8}A = \{1, 2, 3, 4, 5, 6, 7, 8\} B={6,7,8,9,10,11,12}B = \{6, 7, 8, 9, 10, 11, 12\} C={2,4,6,8,10}C = \{2, 4, 6, 8, 10\} What is BCB \cap C? {6,8,10}\{6, 8, 10\} {2,4,6,6,7,8,8,9,10,11,12}\{2, 4, 6, 6, 7, 8, 8, 9, 10, 11, 12\} {2,4,7,11,12}\{2, 4, 7, 11, 12\} {1,2,3,4,5,6,7,8,9,10,11,12}\{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12\} Previous Page Next Page

Studdy Solution

STEP 1

What is this asking? Find the numbers that are *both* in set BB and set CC. Watch out! Don't mix up intersection and union!
Intersection means "what's in *both* sets", while union means "what's in *either* set".

STEP 2

1. Examine Set B
2. Examine Set C
3. Find the Intersection

STEP 3

Alright, let's **kick things off** with set BB!
We've got B={6,7,8,9,10,11,12}B = \{6, 7, 8, 9, 10, 11, 12\}.
Remember these numbers, they're our **VIPs** for this step!

STEP 4

Next up is set CC!
It's got C={2,4,6,8,10}C = \{2, 4, 6, 8, 10\}.
Keep your eyes peeled for these **rockstars**!

STEP 5

Now for the **grand finale**: finding the intersection of BB and CC, written as BCB \cap C.
This means we're looking for the numbers that are in *both* sets BB and CC.

STEP 6

Let's **hunt** for **matching numbers**.
Is 66 in both sets?
Yes! Is 77 in both sets?
Nope, only in BB.
Is 88 in both?
You bet!
How about 99?
No, just in BB. 1010?
Yes, it's in both! 1111 and 1212?
Nah, they're only hanging out in set BB.

STEP 7

So, the numbers that are in *both* BB and CC are 66, 88, and 1010.
That means BC={6,8,10}B \cap C = \{6, 8, 10\}!

STEP 8

The intersection of sets BB and CC is {6,8,10}\{6, 8, 10\}.

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