Math  /  Algebra

QuestionQuestion 9 of 10 This question: 5 point(s) possible
Benjamin \& Associates, a real estate developer, recently built 205 condominiums in McCall, Idaho. The condos were either three-bedroom units or four-bedroom units. If the total number of bedrooms in the entire complex is 732 , how many three-bedroom units are there? How many four-bedroom units are there?
There are \square three-bedroom units and \square four-bedroom units.

Studdy Solution

STEP 1

1. There are a total of 205 condominiums.
2. Each condominium is either a three-bedroom unit or a four-bedroom unit.
3. The total number of bedrooms in all the condominiums is 732.
4. We need to find the number of three-bedroom units and four-bedroom units.

STEP 2

1. Define variables for the number of three-bedroom and four-bedroom units.
2. Set up a system of equations based on the given information.
3. Solve the system of equations.

STEP 3

Define variables for the number of three-bedroom and four-bedroom units.
Let x x be the number of three-bedroom units and y y be the number of four-bedroom units.

STEP 4

Set up a system of equations based on the given information.
Equation 1: The total number of units is 205. x+y=205 x + y = 205
Equation 2: The total number of bedrooms is 732. 3x+4y=732 3x + 4y = 732

STEP 5

Solve the system of equations.
First, solve Equation 1 for y y : y=205x y = 205 - x
Substitute y=205x y = 205 - x into Equation 2: 3x+4(205x)=732 3x + 4(205 - x) = 732
Simplify and solve for x x : 3x+8204x=732 3x + 820 - 4x = 732 x+820=732 -x + 820 = 732
Subtract 820 from both sides: x=732820 -x = 732 - 820 x=88 -x = -88
Multiply both sides by -1: x=88 x = 88

STEP 6

Now, substitute x=88 x = 88 back into the equation for y y : y=20588 y = 205 - 88 y=117 y = 117
So, there are 88 \boxed{88} three-bedroom units and 117 \boxed{117} four-bedroom units.

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