Math  /  Calculus

QuestionQuestion Evaluate using integration by parts. xe4xdx\int x e^{-4 x} d x

Studdy Solution

STEP 1

1. We are given the integral xe4xdx\int x e^{-4x} \, dx.
2. We will use the integration by parts formula: udv=uvvdu\int u \, dv = uv - \int v \, du.

STEP 2

1. Identify uu and dvdv.
2. Differentiate uu to find dudu.
3. Integrate dvdv to find vv.
4. Apply the integration by parts formula.
5. Simplify and solve the remaining integral.

STEP 3

Identify uu and dvdv from the integral xe4xdx\int x e^{-4x} \, dx.
Let: u=x u = x dv=e4xdx dv = e^{-4x} \, dx

STEP 4

Differentiate uu to find dudu.
du=ddx(x)dx=1dx du = \frac{d}{dx}(x) \, dx = 1 \, dx

STEP 5

Integrate dvdv to find vv.
v=e4xdx v = \int e^{-4x} \, dx
To integrate, use the substitution method: Let w=4x w = -4x , then dw=4dx dw = -4 \, dx or dx=14dw dx = -\frac{1}{4} \, dw .
v=ew(14)dw=14ewdw=14ew+C v = \int e^{w} \left(-\frac{1}{4}\right) \, dw = -\frac{1}{4} \int e^{w} \, dw = -\frac{1}{4} e^{w} + C
Substitute back for w w : v=14e4x v = -\frac{1}{4} e^{-4x}

STEP 6

Apply the integration by parts formula udv=uvvdu\int u \, dv = uv - \int v \, du.
xe4xdx=uvvdu \int x e^{-4x} \, dx = uv - \int v \, du
Substitute uu, vv, and dudu:
=x(14e4x)(14e4x)1dx = x \left(-\frac{1}{4} e^{-4x}\right) - \int \left(-\frac{1}{4} e^{-4x}\right) \cdot 1 \, dx
=14xe4x+14e4xdx = -\frac{1}{4} x e^{-4x} + \frac{1}{4} \int e^{-4x} \, dx

STEP 7

Simplify and solve the remaining integral e4xdx\int e^{-4x} \, dx.
We already found that: e4xdx=14e4x \int e^{-4x} \, dx = -\frac{1}{4} e^{-4x}
Substitute this back into the equation:
=14xe4x+14(14e4x) = -\frac{1}{4} x e^{-4x} + \frac{1}{4} \left(-\frac{1}{4} e^{-4x}\right)
=14xe4x116e4x = -\frac{1}{4} x e^{-4x} - \frac{1}{16} e^{-4x}
=14e4x(x+14)+C = -\frac{1}{4} e^{-4x} (x + \frac{1}{4}) + C
Where C C is the constant of integration.
The evaluated integral is:
14e4x(x+14)+C \boxed{-\frac{1}{4} e^{-4x} (x + \frac{1}{4}) + C}

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