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Math

Math Snap

PROBLEM

Question
Graph the line with the equation y=25x+1y = \frac{2}{5}x + 1.

STEP 1

What is this asking?
Draw the line represented by the equation y=25x+1y = \frac{2}{5}x + 1.
Watch out!
Don't mix up the slope and the y-intercept!

STEP 2

1. Find the y-intercept.
2. Find the slope.
3. Plot the y-intercept.
4. Use the slope to find another point.
5. Draw the line.

STEP 3

The y-intercept is the value of yy when x=0x = 0.
Let's substitute x=0x = 0 into our equation:
y=250+1y = \frac{2}{5} \cdot 0 + 1

STEP 4

Any number multiplied by zero is zero, so 250=0\frac{2}{5} \cdot 0 = 0.
y=0+1y = 0 + 1

STEP 5

Adding zero to a number doesn't change the number, so 0+1=10 + 1 = 1.
y=1y = 1

STEP 6

So, our y-intercept is 11, which means the line crosses the y-axis at the point (0,1)(0, 1).

STEP 7

Our equation is in slope-intercept form, which is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept.

STEP 8

In our equation, y=25x+1y = \frac{2}{5}x + 1, the slope mm is 25\frac{2}{5}.
This tells us that for every 5 units we move to the right along the x-axis, we move 2 units up along the y-axis.

STEP 9

We found that the y-intercept is (0,1)(0, 1).
So, let's put a point at (0,1)(0, 1) on our graph!

STEP 10

Starting from our y-intercept (0,1)(0, 1), we can use the slope 25\frac{2}{5} to find another point.

STEP 11

The slope tells us to move 5 units to the right (+5+5 to the xx-value) and 2 units up (+2+2 to the yy-value).

STEP 12

Starting at (0,1)(0, 1), adding 55 to xx gives us 0+5=50 + 5 = 5, and adding 22 to yy gives us 1+2=31 + 2 = 3.

STEP 13

So, our second point is (5,3)(5, 3).
Let's plot this point on the graph!

STEP 14

Now that we have two points, (0,1)(0, 1) and (5,3)(5, 3), we can draw a straight line through them.
Extend the line in both directions to show that it continues infinitely.

SOLUTION

The graph of the line y=25x+1y = \frac{2}{5}x + 1 is a straight line passing through the points (0,1)(0, 1) and (5,3)(5, 3).

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