Math / Algebra

QuestionQuestion
Which equation has the solution $x=7$ ?
Answer $4 x-3=-25$ $5 x-4=31$ $8 x+8=104$ $6 x-4=5$

Studdy Solution

STEP 1

1. We need to determine which of the provided equations results in $x=7$ when solved.
2. Each equation is linear and can be solved by isolating $x$ .
3. To verify, we substitute $x=7$ into each equation and check if the equation holds true.

STEP 2

1. Substitute $x=7$ into the first equation $4x - 3 = -25$ and verify.
2. Substitute $x=7$ into the second equation $5x - 4 = 31$ and verify.
3. Substitute $x=7$ into the third equation $8x + 8 = 104$ and verify.
4. Substitute $x=7$ into the fourth equation $6x - 4 = 5$ and verify.

STEP 3

Substitute $x=7$ into the equation $4x - 3 = -25$ .
$4(7) - 3 = 28 - 3 = 25 \neq -25$
Since $25 \neq -25$ , $x=7$ is not the solution for this equation.

STEP 4

Substitute $x=7$ into the equation $5x - 4 = 31$ .
$5(7) - 4 = 35 - 4 = 31$
Since $31 = 31$ , $x=7$ is the solution for this equation.

STEP 5

Substitute $x=7$ into the equation $8x + 8 = 104$ .
$8(7) + 8 = 56 + 8 = 64 \neq 104$
Since $64 \neq 104$ , $x=7$ is not the solution for this equation.

STEP 6

Substitute $x=7$ into the equation $6x - 4 = 5$ .
$6(7) - 4 = 42 - 4 = 38 \neq 5$
Since $38 \neq 5$ , $x=7$ is not the solution for this equation.
The equation that has the solution $x=7$ is:
$5x - 4 = 31$

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QuestionQuestion
Which equation has the solution $x=7$ ?
Answer $4 x-3=-25$ $5 x-4=31$ $8 x+8=104$ $6 x-4=5$

Studdy Solution

STEP 1

1. We need to determine which of the provided equations results in $x=7$ when solved.
2. Each equation is linear and can be solved by isolating $x$ .
3. To verify, we substitute $x=7$ into each equation and check if the equation holds true.

STEP 2

1. Substitute $x=7$ into the first equation $4x - 3 = -25$ and verify.
2. Substitute $x=7$ into the second equation $5x - 4 = 31$ and verify.
3. Substitute $x=7$ into the third equation $8x + 8 = 104$ and verify.
4. Substitute $x=7$ into the fourth equation $6x - 4 = 5$ and verify.

STEP 3

Substitute $x=7$ into the equation $4x - 3 = -25$ .
$4(7) - 3 = 28 - 3 = 25 \neq -25$
Since $25 \neq -25$ , $x=7$ is not the solution for this equation.

STEP 4

Substitute $x=7$ into the equation $5x - 4 = 31$ .
$5(7) - 4 = 35 - 4 = 31$
Since $31 = 31$ , $x=7$ is the solution for this equation.

STEP 5

Substitute $x=7$ into the equation $8x + 8 = 104$ .
$8(7) + 8 = 56 + 8 = 64 \neq 104$
Since $64 \neq 104$ , $x=7$ is not the solution for this equation.

STEP 6

Substitute $x=7$ into the equation $6x - 4 = 5$ .
$6(7) - 4 = 42 - 4 = 38 \neq 5$
Since $38 \neq 5$ , $x=7$ is not the solution for this equation.
The equation that has the solution $x=7$ is:
$5x - 4 = 31$

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QuestionQuestionWhich equation has the solution x=7x=7x=7 ?Answer 4x−3=−254 x-3=-254x−3=−25 5x−4=315 x-4=315x−4=31 8x+8=1048 x+8=1048x+8=104 6x−4=56 x-4=56x−4=5

Studdy Solution

STEP 1

1. We need to determine which of the provided equations results in x=7x=7x=7 when solved.2. Each equation is linear and can be solved by isolating xxx.3. To verify, we substitute x=7x=7x=7 into each equation and check if the equation holds true.

STEP 2

STEP 3

Substitute x=7x=7x=7 into the equation 4x−3=−254x - 3 = -254x−3=−25.4(7)−3=28−3=25≠−25 4(7) - 3 = 28 - 3 = 25 \neq -25 4(7)−3=28−3=25=−25Since 25≠−2525 \neq -2525=−25, x=7x=7x=7 is not the solution for this equation.

STEP 4

Substitute x=7x=7x=7 into the equation 5x−4=315x - 4 = 315x−4=31.5(7)−4=35−4=31 5(7) - 4 = 35 - 4 = 31 5(7)−4=35−4=31Since 31=3131 = 3131=31, x=7x=7x=7 is the solution for this equation.

STEP 5

Substitute x=7x=7x=7 into the equation 8x+8=1048x + 8 = 1048x+8=104.8(7)+8=56+8=64≠104 8(7) + 8 = 56 + 8 = 64 \neq 104 8(7)+8=56+8=64=104Since 64≠10464 \neq 10464=104, x=7x=7x=7 is not the solution for this equation.

STEP 6

Substitute x=7x=7x=7 into the equation 6x−4=56x - 4 = 56x−4=5.6(7)−4=42−4=38≠5 6(7) - 4 = 42 - 4 = 38 \neq 5 6(7)−4=42−4=38=5Since 38≠538 \neq 538=5, x=7x=7x=7 is not the solution for this equation.The equation that has the solution x=7x=7x=7 is:5x−4=31 5x - 4 = 31 5x−4=31

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QuestionQuestion
Which equation has the solution $x=7$ ?
Answer $4 x-3=-25$ $5 x-4=31$ $8 x+8=104$ $6 x-4=5$

1. We need to determine which of the provided equations results in $x=7$ when solved.
2. Each equation is linear and can be solved by isolating $x$ .
3. To verify, we substitute $x=7$ into each equation and check if the equation holds true.

Substitute $x=7$ into the equation $4x - 3 = -25$ .
$4(7) - 3 = 28 - 3 = 25 \neq -25$
Since $25 \neq -25$ , $x=7$ is not the solution for this equation.

Substitute $x=7$ into the equation $5x - 4 = 31$ .
$5(7) - 4 = 35 - 4 = 31$
Since $31 = 31$ , $x=7$ is the solution for this equation.

Substitute $x=7$ into the equation $8x + 8 = 104$ .
$8(7) + 8 = 56 + 8 = 64 \neq 104$
Since $64 \neq 104$ , $x=7$ is not the solution for this equation.

Substitute $x=7$ into the equation $6x - 4 = 5$ .
$6(7) - 4 = 42 - 4 = 38 \neq 5$
Since $38 \neq 5$ , $x=7$ is not the solution for this equation.
The equation that has the solution $x=7$ is:
$5x - 4 = 31$