Math

QuestionAnalyze 400 accidents to find proportions related to alcohol and vehicle involvement. Answer questions based on these ratios.

Studdy Solution

STEP 1

Assumptions1. The total number of accidents is400. . The table provides the distribution of accidents based on the number of vehicles involved and whether alcohol played a role.
3. The numbers in the table represent the number of accidents.

STEP 2

To find the proportion of accidents that involved more than one vehicle, we need to add up the number of accidents that involved2 vehicles and vehicles.
Numberofaccidentswithmorethanonevehicle=Numberofaccidentswith2vehicles+NumberofaccidentswithvehiclesNumber\, of\, accidents\, with\, more\, than\, one\, vehicle = Number\, of\, accidents\, with\,2\, vehicles + Number\, of\, accidents\, with\,\, vehicles

STEP 3

From the table, we see that the number of accidents with2 vehicles is275 and with3 vehicles is50. So, plug in these values into the formula.
Numberofaccidentswithmorethanonevehicle=275+50Number\, of\, accidents\, with\, more\, than\, one\, vehicle =275 +50

STEP 4

Calculate the number of accidents with more than one vehicle.
Numberofaccidentswithmorethanonevehicle=275+50=325Number\, of\, accidents\, with\, more\, than\, one\, vehicle =275 +50 =325

STEP 5

Now, to find the proportion of accidents that involved more than one vehicle, we divide the number of accidents with more than one vehicle by the total number of accidents.
Proportionofaccidentswithmorethanonevehicle=NumberofaccidentswithmorethanonevehicleTotalnumberofaccidentsProportion\, of\, accidents\, with\, more\, than\, one\, vehicle = \frac{Number\, of\, accidents\, with\, more\, than\, one\, vehicle}{Total\, number\, of\, accidents}

STEP 6

Plug in the values for the number of accidents with more than one vehicle and the total number of accidents into the formula.
Proportionofaccidentswithmorethanonevehicle=325400Proportion\, of\, accidents\, with\, more\, than\, one\, vehicle = \frac{325}{400}

STEP 7

Calculate the proportion of accidents with more than one vehicle.
Proportionofaccidentswithmorethanonevehicle=325400=0.8125Proportion\, of\, accidents\, with\, more\, than\, one\, vehicle = \frac{325}{400} =0.8125So, the proportion of accidents that involved more than one vehicle is0.8125 or81.25%. The correct answer is (d) 325/400325 /400 or 81.25%81.25 \%.

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