QuestionI'aps
Fanling tada; 6 IN .
Reflect the figure over the line .
Plot all of the points of the reflected figure.
You may click a plotted point to delete it.
Studdy Solution
STEP 1
What is this asking?
Flip this triangle over the line as if it were a mirror!
Watch out!
Make sure you flip the triangle *over* the line , not the x-axis.
It's a *reflection*, not a slide!
STEP 2
1. Find the distance of each point from the line of reflection.
2. Reflect each point.
STEP 3
Alright, let's look at our first point, .
We want to find how far it is from the line .
Since we're focusing on the vertical distance, we look at the y-values.
The y-value of our point is **5**, and the y-value of the reflection line is **-1**.
The distance is the difference between these two values: .
So, our first point is **6** units away from the line of reflection.
STEP 4
Now for point .
It has the same y-value as our first point, which is **5**.
Since the line of reflection is still , the distance is the same as before: units.
STEP 5
Last point!
This one is .
Its y-value is **8**.
The distance from the line is units.
STEP 6
Our first point is **6** units *above* the line .
To reflect it, we need to go **6** units *below* the line.
Since the line is at , we subtract **6** from **-1**: .
The x-value stays the same, so our reflected point is .
STEP 7
Point two is also **6** units above .
So, we move **6** units below the line: .
The x-value remains unchanged, giving us the reflected point .
STEP 8
Finally, point three is **9** units above .
Moving **9** units below the line gives us .
Keeping the same x-value, our reflected point is .
STEP 9
The reflected triangle has vertices at , , and .
Plot these points!
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