Math  /  Algebra

QuestionRewrite each equation as requested. (a) Rewrite as a logarithmic equation. 20=12^{0}=1 (b) Rewrite as an exponential equation. log5125=2\log _{5} \frac{1}{25}=-2 (a) log=\log _{\square} \square= \square (b) =\square= \square

Studdy Solution

STEP 1

1. We need to convert between exponential and logarithmic forms.
2. The base of the exponential form becomes the base of the logarithm and vice versa.
3. The logarithm of a number is the exponent to which the base must be raised to produce that number.

STEP 2

1. Rewrite the given exponential equation as a logarithmic equation.
2. Rewrite the given logarithmic equation as an exponential equation.

STEP 3

Identify the base, exponent, and result in the exponential equation 20=12^{0} = 1.
The base is 22, the exponent is 00, and the result is 11.

STEP 4

Rewrite the exponential equation 20=12^{0} = 1 as a logarithmic equation.
The logarithmic form is:
log21=0\log_{2} 1 = 0
This matches the format log=\log_{\square} \square = \square.

STEP 5

Identify the base, result, and exponent in the logarithmic equation log5125=2\log_{5} \frac{1}{25} = -2.
The base is 55, the result is 125\frac{1}{25}, and the exponent is 2-2.

STEP 6

Rewrite the logarithmic equation log5125=2\log_{5} \frac{1}{25} = -2 as an exponential equation.
The exponential form is:
52=1255^{-2} = \frac{1}{25}
This matches the format =\square = \square.
The rewritten equations are: (a) log21=0\log_{2} 1 = 0 (b) 52=1255^{-2} = \frac{1}{25}

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