Math  /  Algebra

QuestionRewrite each expression as an equivalent ratio of logs using the indicated base. log7(14)\log _{7}(14) to base ee. \square Question Help: Written Example Submit Question

Studdy Solution

STEP 1

What is this asking? Rewrite log7(14)\log_7(14) using base ee instead of base 7. Watch out! Remember the change of base formula and don't mix up the different parts of the logarithm!

STEP 2

1. Recall the change of base formula.
2. Apply the change of base formula.

STEP 3

The **change of base formula** is super handy!
It lets us switch from one base to another.
It says: loga(b)=logc(b)logc(a) \log_a(b) = \frac{\log_c(b)}{\log_c(a)} Where aa is the **original base**, bb is the **argument**, and cc is the **new base** we want.

STEP 4

In our problem, we have log7(14)\log_7(14), so our **original base** aa is **7**, and our **argument** bb is **14**.
We want to change to base ee, so our **new base** cc is **e**.
Let's plug these values into our formula: log7(14)=loge(14)loge(14) \log_7(14) = \frac{\log_e(14)}{\log_e(14)} Remember, loge(x)\log_e(x) is the same as ln(x)\ln(x), the **natural logarithm**.
So we can rewrite our answer as: log7(14)=ln(14)ln(7) \log_7(14) = \frac{\ln(14)}{\ln(7)} Boom! We've successfully changed the base!

STEP 5

ln(14)ln(7)\frac{\ln(14)}{\ln(7)}

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