Math  /  Algebra

QuestionRewrite f(x)f(x) in factored form, but do not simplify: f(x)=3x3+10x225x3x2+17x+20=f(x)=\frac{3 x^{3}+10 x^{2}-25 x}{3 x^{2}+17 x+20}=

Studdy Solution

STEP 1

1. We are given a rational function f(x)=3x3+10x225x3x2+17x+20 f(x) = \frac{3x^3 + 10x^2 - 25x}{3x^2 + 17x + 20} .
2. The goal is to express both the numerator and the denominator in factored form.
3. We will not simplify the expression after factoring.

STEP 2

1. Factor the numerator 3x3+10x225x 3x^3 + 10x^2 - 25x .
2. Factor the denominator 3x2+17x+20 3x^2 + 17x + 20 .

STEP 3

Factor the numerator 3x3+10x225x 3x^3 + 10x^2 - 25x .
First, factor out the greatest common factor (GCF) from the numerator:
3x3+10x225x=x(3x2+10x25) 3x^3 + 10x^2 - 25x = x(3x^2 + 10x - 25)
Next, factor the quadratic 3x2+10x25 3x^2 + 10x - 25 . This can be done using the quadratic formula or by trial and error for integer roots. Assume it factors as:
3x2+10x25=(3x5)(x+5) 3x^2 + 10x - 25 = (3x - 5)(x + 5)
Thus, the numerator in factored form is:
x(3x5)(x+5) x(3x - 5)(x + 5)

STEP 4

Factor the denominator 3x2+17x+20 3x^2 + 17x + 20 .
Assume it factors as:
3x2+17x+20=(3x+5)(x+4) 3x^2 + 17x + 20 = (3x + 5)(x + 4)

STEP 5

Rewrite f(x) f(x) in factored form using the factored numerator and denominator:
f(x)=x(3x5)(x+5)(3x+5)(x+4) f(x) = \frac{x(3x - 5)(x + 5)}{(3x + 5)(x + 4)}

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