Math

Question Rewrite f(x)=4(x1)22f(x)=4(x-1)^{2}-2 in the form f(x)=ax2+bx+cf(x)=a x^{2}+b x+c.

Studdy Solution

STEP 1

Assumptions
1. The given function is f(x)=4(x1)22f(x)=4(x-1)^{2}-2.
2. We need to rewrite the function in the form f(x)=ax2+bx+cf(x)=ax^{2}+bx+c.

STEP 2

Expand the squared term in the function using the formula (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2.
f(x)=4[(x)22(x)(1)+(1)2]2f(x) = 4[(x)^2 - 2(x)(1) + (1)^2] - 2

STEP 3

Distribute the 4 across the terms inside the brackets.
f(x)=4(x22x+1)2f(x) = 4(x^2 - 2x + 1) - 2

STEP 4

Multiply each term inside the brackets by 4.
f(x)=4x28x+42f(x) = 4x^2 - 8x + 4 - 2

STEP 5

Combine the constant terms.
f(x)=4x28x+2f(x) = 4x^2 - 8x + 2

STEP 6

Now the function is in the desired form f(x)=ax2+bx+cf(x)=ax^{2}+bx+c where a=4a=4, b=8b=-8, and c=2c=2.
f(x)=4x28x+2f(x)=4x^{2}-8x+2

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord