Math  /  Algebra

QuestionSalma is walking. D(t)D(t), given below, is her distance in kilometers from Glen City after tt hours of walking. D(t)=12.84tD(t)=12.8-4 t
Complete the following statements.
Let D1D^{-1} be the inverse function of DD. Take xx to be an output of the function DD. That is, x=D(t)x=D(t) and t=D1(x)t=D^{-1}(x). (a) Which statement best describes D1(x)D^{-1}(x) ?
The ratio of the amount of time she has walked (in hours) to her distance from Glen City (in kilometers), xx.
The reciprocal of her distance from Glen City (in kilometers) after walking xx hours.
The amount of time she has walked (in hours) when she is xx kilometers from Glen City. Her distance from Glen City (in kilometers) after she has walked xx hours. (b) D1(x)=D^{-1}(x)= \square (c) D1(8.4)=D^{-1}(8.4)= \square

Studdy Solution

STEP 1

What is this asking? Given Salma's distance from Glen City over time, how much time does it take her to reach a certain distance? Watch out! Don't mix up the input and output of the inverse function! D(t)D(t) tells us the distance after a given time, but D1(x)D^{-1}(x) tells us the *time* it takes to reach a given *distance*.

STEP 2

1. Understand the Function
2. Find the Inverse Function
3. Calculate the Specific Time

STEP 3

Alright, so we've got this function D(t)=12.84tD(t) = 12.8 - 4t, where tt is the **time** Salma's been walking in hours, and D(t)D(t) is her **distance** from Glen City in kilometers.
So, if we plug in a time, it tells us how far she is from Glen City at that time!

STEP 4

For example, when t=0t = 0 (when she starts walking), her distance is D(0)=12.840=12.8D(0) = 12.8 - 4 \cdot 0 = 12.8 kilometers.
This means Salma **starts** 12.8 kilometers away from Glen City.

STEP 5

The 4t-4t part tells us that for every hour (t=1t=1) she walks, her distance from Glen City *decreases* by 4 kilometers.
That's our **rate of change**!

STEP 6

Now, we want to find the *inverse* function, D1(x)D^{-1}(x).
This function will do the *opposite* of D(t)D(t).
We'll give it a **distance**, xx, and it will tell us the **time** it took Salma to get that far from Glen City.

STEP 7

To find the inverse, we **swap** tt and xx in our original equation: x=12.84tx = 12.8 - 4t.
Now, we **solve for** tt.

STEP 8

First, we want to **isolate** the term with tt.
We can do this by **subtracting** 12.8 from both sides of the equation: x12.8=4tx - 12.8 = -4t.

STEP 9

Next, we **divide both sides** by 4-4 to get tt by itself: x12.84=t\frac{x - 12.8}{-4} = t.

STEP 10

So, our inverse function is D1(x)=x12.84D^{-1}(x) = \frac{x - 12.8}{-4}.
This tells us the **time** it takes Salma to be xx kilometers from Glen City.

STEP 11

We want to find D1(8.4)D^{-1}(8.4), which means we want to know how long it takes Salma to be **8.4 kilometers** from Glen City.

STEP 12

We **plug in** x=8.4x = 8.4 into our inverse function: D1(8.4)=8.412.84D^{-1}(8.4) = \frac{8.4 - 12.8}{-4}.

STEP 13

Now we **calculate**: D1(8.4)=4.44=1.1D^{-1}(8.4) = \frac{-4.4}{-4} = 1.1.

STEP 14

So, it takes Salma **1.1 hours** to be 8.4 kilometers from Glen City.

STEP 15

(a) The amount of time she has walked (in hours) when she is xx kilometers from Glen City. (b) D1(x)=x12.84D^{-1}(x) = \frac{x - 12.8}{-4} (c) D1(8.4)=1.1D^{-1}(8.4) = 1.1

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