Math  /  Algebra

QuestionSamantha invested a total of $154,000\$ 154,000 in two accounts. The first account earned 19%19 \% after one year. However, the second account suffered a 15%15 \% loss in the same time. At the end of one year, the total amount of money gained was $4,780\$ 4,780. \ \square \sigma^{5}at at 19 \%P$ P \$ \square 0^{6}at at 15 \%$

Studdy Solution

STEP 1

1. Samantha invested a total of \$154,000 in two accounts.
2. The first account earned 19% interest after one year.
3. The second account suffered a 15% loss after one year.
4. The total amount of money gained from both accounts was \$4,780 after one year.

STEP 2

1. Define variables for the amounts invested in each account.
2. Set up equations based on the given conditions.
3. Solve the system of equations to find the amounts invested in each account.

STEP 3

Let x x be the amount invested in the first account (19% gain), and y y be the amount invested in the second account (15% loss).

STEP 4

Set up the equation for the total investment: x+y=154,000 x + y = 154,000
Set up the equation for the total gain: 0.19x0.15y=4,780 0.19x - 0.15y = 4,780

STEP 5

Solve the system of equations:
First, solve for y y in terms of x x from the first equation: y=154,000x y = 154,000 - x
Substitute y=154,000x y = 154,000 - x into the second equation: 0.19x0.15(154,000x)=4,780 0.19x - 0.15(154,000 - x) = 4,780
Simplify and solve for x x : 0.19x0.15×154,000+0.15x=4,780 0.19x - 0.15 \times 154,000 + 0.15x = 4,780 0.34x23,100=4,780 0.34x - 23,100 = 4,780 0.34x=27,880 0.34x = 27,880 x=27,8800.34 x = \frac{27,880}{0.34} x=82,000 x = 82,000
Now, substitute back to find y y : y=154,00082,000 y = 154,000 - 82,000 y=72,000 y = 72,000
The amounts invested in each account are: First account: \$82,000 Second account: \$72,000

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