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Math  /  Numbers & Operations

Question- Sample B has a mass of 12.0 g and a volume or 0.0 - Sample C has a mass of 12.0 g and a volume of 3.0 ml .
10. A graduated cylinder contains 17.5 ml of water. When a metal cube is placed onto the cylinder, its water level rises to 20.3 ml . Calculate the following: - Volume of the cube: \qquad ml - Volume of the cube \qquad cm3\mathrm{cm}^{3}

Studdy Solution

STEP 1

1. The volume of the cube can be determined by the displacement of water.
2. 1 milliliter (ml) is equivalent to 1 cubic centimeter (cm³).
3. We need to find the volume change in the graduated cylinder when the cube is submerged.

STEP 2

1. Determine the volume of the cube based on the water displacement.
2. Convert the volume from milliliters to cubic centimeters.

STEP 3

Calculate the volume of water displaced by the cube by subtracting the initial water level from the final water level.
Volume of the cube=Final water level−Initial water level \text{Volume of the cube} = \text{Final water level} - \text{Initial water level}
Volume of the cube=20.3 ml−17.5 ml \text{Volume of the cube} = 20.3\, \text{ml} - 17.5\, \text{ml}

STEP 4

Perform the subtraction to find the volume of the cube.
Volume of the cube=20.3 ml−17.5 ml=2.8 ml \text{Volume of the cube} = 20.3\, \text{ml} - 17.5\, \text{ml} = 2.8\, \text{ml}

STEP 5

Convert the volume from milliliters to cubic centimeters.
Since 1 ml=1 cm3 \text{Since } 1\, \text{ml} = 1\, \text{cm}^3
Volume of the cube=2.8 cm3 \text{Volume of the cube} = 2.8\, \text{cm}^3
The volume of the cube is 2.8\boxed{2.8} ml, which is also 2.8\boxed{2.8} cm3\mathrm{cm}^{3}.

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