Math  /  Algebra

Question\checkmark Select an answer he how mm
Infinitely many: All real numbers
No solution One solution +33+33
Select an answer 6(2x+1)5=12x10-6(-2 x+1)-5=12 x-10

Studdy Solution

STEP 1

What is this asking? We need to figure out how many solutions the equation 6(2x+1)5=12x10-6(-2x + 1) - 5 = 12x - 10 has. Watch out! Don't rush!
It's easy to make mistakes with the signs when distributing.

STEP 2

1. Simplify the equation
2. Analyze the result

STEP 3

Let's **distribute** the 6-6 across the terms inside the parentheses.
Remember, a negative times a negative is a positive, and a negative times a positive is a negative!
So, we have 62x=12x-6 \cdot -2x = 12x and 61=6-6 \cdot 1 = -6.
Our equation becomes 12x65=12x1012x - 6 - 5 = 12x - 10.

STEP 4

Now, let's **combine** those **like terms** on the left side.
We have 6-6 and 5-5.
Adding those together gives us 11-11.
So, our equation is now 12x11=12x1012x - 11 = 12x - 10.

STEP 5

To **isolate** the xx term, we'll subtract 12x12x from both sides of the equation.
This gives us 12x12x11=12x12x1012x - 12x - 11 = 12x - 12x - 10, which simplifies to 11=10-11 = -10.

STEP 6

Whoa, hold on!
Does 11-11 actually equal 10-10?
Nope, definitely not!
This means there's **no value** of xx that will make the original equation true.

STEP 7

Since 11-11 does not equal 10-10, there is **no solution** to the given equation.

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