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Math  /  Numbers & Operations

QuestionSelect either < or > to make the statement true. −20…9−10−100−13_13\begin{array}{l} -20 \ldots \quad 9 \\ -10 \quad-100 \\ -13 \_13 \end{array}

Studdy Solution

STEP 1

1. The problem involves comparing two numbers on the real number line.
2. We need to determine whether the first number is less than or greater than the second number for each pair.

STEP 2

1. Compare the first pair of numbers: −20-20 and 99.
2. Compare the second pair of numbers: −10-10 and −100-100.
3. Compare the third pair of numbers: −13-13 and 1313.

STEP 3

Compare the numbers −20-20 and 99. Since −20-20 is to the left of 99 on the number line, it is less than 99. −20<9 -20 < 9

STEP 4

Compare the numbers −10-10 and −100-100. Since −100-100 is to the left of −10-10 on the number line, it is less than −10-10. −100<−10 -100 < -10

STEP 5

Compare the numbers −13-13 and 1313. Since −13-13 is to the left of 1313 on the number line, it is less than 1313. −13<13 -13 < 13
RESULT: The correct inequality symbols to make the statements true are: −20<9−100<−10−13<13\begin{array}{l} -20 < 9 \\ -100 < -10 \\ -13 < 13 \end{array}

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