Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

Select Function Set 2, f(x)=xf(x)=\sqrt{x} and g(x)=x24g(x)=x^{2}-4, and check the Values box. Using the xx-slider, set x=3x=3. Complete parts 1 through 3 below.
Use the interactive figure to find your answer. Use the left and right arrow keys to move along a slider as needed. Click here to launch the interactive figure.
Part 1: Using the graph of g , evaluate g(3)\mathrm{g}(3).
g(3)=g(3)= \square 5 (Type an integer or decimal rounded to two decimal places as needed.)
Part 2: Using the graph of ff and the value of g(3)g(3) found in Part 1, evaluate f(g(3))f(g(3)).
f(g(3))=\mathrm{f}(\mathrm{g}(3))= \square (Type an integer or decimal rounded to two decimal places as needed.)

STEP 1

What is this asking?
We're given two functions, f(x)=xf(x) = \sqrt{x} and g(x)=x24g(x) = x^2 - 4, and we need to find g(3)g(3) and then use that result to find f(g(3))f(g(3)).
Watch out!
Make sure to apply the functions in the correct order!
We need g(3)g(3) first, then we plug that result into f(x)f(x).
Also, remember the order of operations when evaluating g(3)g(3).

STEP 2

1. Evaluate g(3)g(3)
2. Evaluate f(g(3))f(g(3))

STEP 3

We're given the function g(x)=x24g(x) = x^2 - 4.
To find g(3)g(3), we substitute x=3x = 3 into the function:
g(3)=(3)24g(3) = (3)^2 - 4

STEP 4

Now, let's calculate the result!
First, we square the 3:
g(3)=94g(3) = 9 - 4 Then, we subtract 4 from 9:
g(3)=5g(3) = 5 So, g(3)=5g(3) = \textbf{5}!

STEP 5

We just found that g(3)=5g(3) = \textbf{5}.
Now, we need to find f(g(3))f(g(3)), which is the same as finding f(5)f(5) since g(3)g(3) is 5.

STEP 6

Our function f(x)f(x) is defined as f(x)=xf(x) = \sqrt{x}.
We substitute our value of 5 for xx:
f(5)=5f(5) = \sqrt{5}

STEP 7

Now, we calculate the square root of 5:
f(5)2.236f(5) \approx 2.236 Rounding to two decimal places, we get 2.24\textbf{2.24}.

SOLUTION

Part 1: g(3)=5g(3) = 5
Part 2: f(g(3))=2.24f(g(3)) = 2.24

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord