Math

QuestionSid spent \6.80onwrappingpaperand$7.35onribbon.Hewrote6.80 on wrapping paper and \$7.35 on ribbon. He wrote (6.80+7.35) \div 8$ to find the cost per gift. How many gifts did he wrap?

Studdy Solution

STEP 1

Assumptions1. The cost of wrapping paper is 6.80.Thecostofribbonis6.80. The cost of ribbon is 7.353. All gifts are identical and thus cost the same to wrap4. Sid used the expression (6.80+7.35)÷8(6.80+7.35) \div8 to calculate the cost per gift

STEP 2

First, we need to understand the expression Sid used to calculate the cost per gift. The expression is a sum of two costs divided by a number.
Costpergift=(Costofwrappingpaper+Costofribbon)÷NumberofgiftsCost\, per\, gift = (Cost\, of\, wrapping\, paper + Cost\, of\, ribbon) \div Number\, of\, gifts

STEP 3

Now, plug in the given values for the cost of wrapping paper and ribbon into the expression.
Costpergift=(6.80+7.35)÷NumberofgiftsCost\, per\, gift = (6.80 +7.35) \div Number\, of\, gifts

STEP 4

Calculate the sum of the cost of wrapping paper and ribbon.
Costpergift=14.15÷NumberofgiftsCost\, per\, gift =14.15 \div Number\, of\, gifts

STEP 5

From the problem, we know that Sid used the number8 in the denominator of his expression. This number represents the number of gifts.
Costpergift=14.15÷8Cost\, per\, gift =14.15 \div8

STEP 6

Since the expression Sid used to calculate the cost per gift is equal to the total cost divided by8, we can conclude that Sid wrapped8 gifts.
Sid wrapped8 gifts.

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