Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

Simplify.
5y48y327y55 y \sqrt{48 y^{3}}-\sqrt{27 y^{5}} Assume that the variable represents a positive real number.

STEP 1

1. The variable y y represents a positive real number.
2. We need to simplify the expression by simplifying the square roots and combining like terms if possible.

STEP 2

1. Simplify the square root expressions individually.
2. Combine the simplified expressions.

STEP 3

Simplify the first square root expression 48y3 \sqrt{48 y^3} .
First, factor 48 48 into its prime factors:
48=24×3 48 = 2^4 \times 3 Rewrite the expression under the square root:
48y3=24×3×y3 \sqrt{48 y^3} = \sqrt{2^4 \times 3 \times y^3} Separate the perfect squares from the non-perfect squares:
=(22)2×3×y2×y = \sqrt{(2^2)^2 \times 3 \times y^2 \times y} Take the square root of the perfect squares:
=22×y×3y = 2^2 \times y \times \sqrt{3y} =4y3y = 4y \sqrt{3y}

STEP 4

Simplify the second square root expression 27y5 \sqrt{27 y^5} .
First, factor 27 27 into its prime factors:
27=33 27 = 3^3 Rewrite the expression under the square root:
27y5=33×y5 \sqrt{27 y^5} = \sqrt{3^3 \times y^5} Separate the perfect squares from the non-perfect squares:
=32×3×(y2)2×y = \sqrt{3^2 \times 3 \times (y^2)^2 \times y} Take the square root of the perfect squares:
=3×y2×3y = 3 \times y^2 \times \sqrt{3y} =3y23y = 3y^2 \sqrt{3y}

STEP 5

Substitute the simplified square root expressions back into the original expression:
5y×4y3y3y23y 5y \times 4y \sqrt{3y} - 3y^2 \sqrt{3y} =20y23y3y23y = 20y^2 \sqrt{3y} - 3y^2 \sqrt{3y}

SOLUTION

Combine like terms:
=(20y23y2)3y = (20y^2 - 3y^2) \sqrt{3y} =17y23y = 17y^2 \sqrt{3y} The simplified expression is:
17y23y \boxed{17y^2 \sqrt{3y}}

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord