Math

QuestionSimplify (3ab3)3\left(\frac{3 a}{b^{-3}}\right)^{3} using only positive exponents.

Studdy Solution

STEP 1

Assumptions1. The expression to be simplified is (3ab3)3\left(\frac{3 a}{b^{-3}}\right)^{3}. . The exponent rule states that (am)n=amn(a^m)^n = a^{mn}.
3. The exponent rule also states that an=1ana^{-n} = \frac{1}{a^n}.

STEP 2

First, we will apply the exponent rule to the expression. This rule states that (am)n=amn(a^m)^n = a^{mn}.
\left(\frac{ a}{b^{-}}\right)^{} = \left(^ a^\right) / \left(b^{-*}\right)

STEP 3

Now, calculate the values of 333^3 and 33-3*3.
(3ab3)3=(27a3)/(b9)\left(\frac{3 a}{b^{-3}}\right)^{3} = \left(27 a^3\right) / \left(b^{-9}\right)

STEP 4

Next, we will apply the exponent rule that states an=1ana^{-n} = \frac{1}{a^n} to b9b^{-9}.
(3ab3)3=(27a3)/(1b9)\left(\frac{3 a}{b^{-3}}\right)^{3} = \left(27 a^3\right) / \left(\frac{1}{b^9}\right)

STEP 5

Now, simplify the expression by multiplying the numerator and denominator by b9b^9.
(3ab3)3=27a3b9\left(\frac{3 a}{b^{-3}}\right)^{3} =27 a^3 b^9The simplified expression with only positive exponents is 27a3b927 a^3 b^9.

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