Math  /  Trigonometry

QuestionSimplify the expression (7.3)
7. 2sin10θcos10θ2 \sin 10 \theta \cos 10 \theta

Studdy Solution

STEP 1

1. The expression involves trigonometric functions.
2. We are asked to simplify the expression using trigonometric identities.
3. The double angle identity for sine can be used here.

STEP 2

1. Identify the appropriate trigonometric identity.
2. Apply the identity to simplify the expression.

STEP 3

Recognize that the expression 2sin10θcos10θ 2 \sin 10\theta \cos 10\theta can be simplified using the double angle identity for sine:
sin2A=2sinAcosA \sin 2A = 2 \sin A \cos A
In this case, A=10θ A = 10\theta .

STEP 4

Apply the double angle identity:
2sin10θcos10θ=sin(2×10θ) 2 \sin 10\theta \cos 10\theta = \sin(2 \times 10\theta)
Which simplifies to:
sin(20θ) \sin(20\theta)
The simplified expression is:
sin(20θ) \boxed{\sin(20\theta)}

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