Math

QuestionSimplify: x3y3/x3y2x^{3} y^{3} / x^{3} y^{2}. Choose the correct answer: a. xyx y, b. xx, c. yy, d. xy/xx y / x.

Studdy Solution

STEP 1

Assumptions1. The expression is x3y3/x3yx^{3} y^{3} / x^{3} y^{} . We are asked to simplify the expression3. The rules of exponents apply, specifically the rule that states am/an=amna^{m} / a^{n} = a^{m-n}

STEP 2

We can simplify the expression by applying the rule of exponents separately to the xx terms and the yy terms.
xy/xy2=xy2x^{} y^{} / x^{} y^{2} = x^{-} y^{-2}

STEP 3

Subtract the exponents to simplify the expression.
x33y32=x0y1x^{3-3} y^{3-2} = x^{0} y^{1}

STEP 4

Any number (except zero) raised to the power of zero is1. Therefore, x0=1x^{0} =1. Substitute this into the expression.
x0y1=1y1x^{0} y^{1} =1 \cdot y^{1}

STEP 5

implify the expression.
1y1=y1 \cdot y^{1} = ySo, the simplified form of x3y3/x3y2x^{3} y^{3} / x^{3} y^{2} is yy.

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