Math  /  Trigonometry

Questionsin(π/2)=\sin (\pi / 2)= \square and sin(3π/2)=\sin (3 \pi / 2)= \square

Studdy Solution

STEP 1

1. The problem involves evaluating the sine function at specific angles.
2. The angles given are in radians.
3. Knowledge of the unit circle and the properties of the sine function is necessary.

STEP 2

1. Evaluate sin(π/2)\sin(\pi/2).
2. Evaluate sin(3π/2)\sin(3\pi/2).

STEP 3

To evaluate sin(π/2)\sin(\pi/2), we use the unit circle. The angle π/2\pi/2 radians corresponds to 90 degrees, which is located at the top of the unit circle. At this position, the y-coordinate (which represents the sine value) is 1.
sin(π/2)=1\sin(\pi/2) = 1

STEP 4

To evaluate sin(3π/2)\sin(3\pi/2), we again use the unit circle. The angle 3π/23\pi/2 radians corresponds to 270 degrees, which is located at the bottom of the unit circle. At this position, the y-coordinate (which represents the sine value) is -1.
sin(3π/2)=1\sin(3\pi/2) = -1
The values are: sin(π/2)=1\sin(\pi/2) = \boxed{1} sin(3π/2)=1\sin(3\pi/2) = \boxed{-1}

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