Math

QuestionFind the general solution for sin(x30)=cos2x\sin (x-30)=\cos 2x.

Studdy Solution

STEP 1

Assumptions1. We are looking for the general solution to the trigonometric equation sin(x30)=cosx\sin (x-30)=\cos x. . We will use the identity \cosx =1 -\sin^ x to transform the equation into a form that can be solved more easily.

STEP 2

First, replace cos2x\cos2x in the equation with the identity 12sin2x1 -2\sin^2 x.
sin(x30)=12sin2x\sin (x-30)=1 -2\sin^2 x

STEP 3

Rearrange the equation to isolate the sin2x\sin^2 x term.
2sin2x+sin(x30)1=02\sin^2 x + \sin (x-30) -1 =0

STEP 4

Now, we have a quadratic equation in terms of sinx\sin x. Let's make a substitution to simplify the equation. Let y=sinxy = \sin x.
2y2+ysin301=02y^2 + y\sin30 -1 =0

STEP 5

We know that sin30=0.5\sin30 =0.5, so we can substitute this value into the equation.
2y2+0.5y1=02y^2 +0.5y -1 =0

STEP 6

Now, we have a quadratic equation in yy. We can solve this equation using the quadratic formula y=b±b24ac2ay = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}.
y=0.5±(0.5)242(1)22y = \frac{-0.5 \pm \sqrt{(0.5)^2 -4*2*(-1)}}{2*2}

STEP 7

olve for yy.
y=0.5±0.25+4y = \frac{-0.5 \pm \sqrt{0.25 +}}{4}

STEP 8

implify the equation.
y=0.5±8.254y = \frac{-0.5 \pm \sqrt{8.25}}{4}

STEP 9

Calculate the values for yy.
y=.5±2.874y = \frac{-.5 \pm2.87}{4}

STEP 10

We get two solutions for yy.
y=0.5+2.874=0.59y = \frac{-0.5 +2.87}{4} =0.59y2=0.52.874=0.84y2 = \frac{-0.5 -2.87}{4} = -0.84

STEP 11

Remember that y=sinxy = \sin x, so we can write the solutions in terms of xx.
sinx=0.59\sin x =0.59sinx=0.84\sin x = -0.84

STEP 12

Now, we can find the general solutions for xx using the inverse sine function.
x=arcsin(0.59)+2nπx = \arcsin(0.59) +2n\pix=πarcsin(0.84)+2nπx = \pi - \arcsin(0.84) +2n\piwhere nn is an integer.

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