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Question 30 of 40 (1 point) I Question Attempt: 1 of 3
Jonath
Smart phone: Among 240 cell phone owners aged 18-24 surveyed, 108 said their phone was an Android phone.
Perform the following.
Part 1 of 3
(a) Find a point estimate for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
The point estimate for the proportion of cell phone owners aged 182418-24 who have android phone is 0.450 .
Part 2 of 3
(b) Construct a 90%90 \% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone. Round the answer to at least three decimal places.
A 90%90 \% confidence interval for the proportion of cell phone owners aged 18-24 who have an Android phone is
0.397<p<0.5030.397<p<0.503 Part: 2/32 / 3
Part 3 of 3
(c) Assume that an advertisement claimed that 38%38 \% of cell phone owners aged 18-24 have an Android phone. Does the confidence interval contradict this
claim? claim?
The confidence interval \square (Choose one) contradict the claim, because 0.38 (Choose one) contained in the confidence interval.
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STEP 1

What is this asking?
Out of 240 young cell phone owners, 108 have Androids.
We need to estimate how common Android phones are among this age group and see if it challenges an ad's claim of 38% Android ownership.
Watch out!
Don't mix up the number of people surveyed with the number who own Androids.
Also, remember that a confidence interval gives a range of plausible values, not just a single number.

STEP 2

1. Calculate the Point Estimate
2. Construct the Confidence Interval
3. Evaluate the Advertisement's Claim

STEP 3

Let's dive in!
We're given that 108108 out of 240240 young cell phone owners have Androids.
To get a point estimate for the proportion, we simply divide the number of Android owners by the total number surveyed.

STEP 4

So, our calculation is 108240\frac{108}{240}.
This simplifies to 0.450.45.
This means our point estimate is 0.450.45, or \textbf{45%}.

STEP 5

Now, let's build a \textbf{90% confidence interval}.
This interval will give us a range of plausible values for the true proportion of Android owners.
The formula for a confidence interval is: Point Estimate±Margin of Error\text{Point Estimate} \pm \text{Margin of Error}.

STEP 6

The margin of error is calculated as: Critical ValueStandard Error\text{Critical Value} \cdot \text{Standard Error}.
For a 90% confidence level, the critical value (from a Z-table) is approximately 1.6451.645.

STEP 7

The standard error is calculated as p(1p)n\sqrt{\frac{p(1-p)}{n}}, where pp is our point estimate (0.450.45) and nn is our sample size (240240).
Plugging in the values, we get 0.45(10.45)2400.24752400.001030.032\sqrt{\frac{0.45 \cdot (1-0.45)}{240}} \approx \sqrt{\frac{0.2475}{240}} \approx \sqrt{0.00103} \approx 0.032.

STEP 8

Now, we can calculate the margin of error: 1.6450.0320.0531.645 \cdot 0.032 \approx 0.053.

STEP 9

Finally, let's construct the confidence interval: 0.45±0.0530.45 \pm 0.053.
This gives us a range of (0.450.053)(0.45 - 0.053) to (0.45+0.053)(0.45 + 0.053), or 0.3970.397 to 0.5030.503.

STEP 10

The advertisement claims that 38%38\% of young cell phone owners have Androids.
Our \textbf{90% confidence interval} is from 0.3970.397 to 0.5030.503.

STEP 11

Since 0.380.38 (or 38%38\%) is not within our confidence interval, the interval does contradict the advertisement's claim.

SOLUTION

The point estimate for Android phone ownership is 0.450.45.
The 90% confidence interval is (0.397,0.503)(0.397, 0.503).
This interval contradicts the advertisement's claim of 38% Android ownership.

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