Math

QuestionSolve 3ax+4ax=5ax+43ax + 4ax = 5ax + 4 for xx, given that a0a \neq 0.

Studdy Solution

STEP 1

Assumptions1. The equation is 3ax+4ax=5ax+43 a x+4 a x=5 a x+4 . a0a \neq0

STEP 2

First, we simplify the equation by combining like terms on both sides. On the left side, we combine ax a x and 4ax4 a x.
ax+4ax=7ax a x +4 a x =7 a x

STEP 3

Now, we substitute the simplified left side back into the original equation.
7ax=5ax+7 a x =5 a x +

STEP 4

Next, we isolate the terms with xx on one side of the equation. We do this by subtracting ax a x from both sides of the equation.
7axax=47 a x - a x =4

STEP 5

implify the left side of the equation.
2ax=42 a x =4

STEP 6

Now, we isolate xx by dividing both sides of the equation by 2a2 a.
x=42ax = \frac{4}{2 a}

STEP 7

Finally, we simplify the right side of the equation to find the value of xx.
x=42a=2ax = \frac{4}{2 a} = \frac{2}{a}So, the solution to the equation 3ax+4ax=5ax+43 a x+4 a x=5 a x+4 for xx is x=2ax = \frac{2}{a}.

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