QuestionSolve for $c$ in the equation $6 c + 1 = -2$ .

Studdy Solution

STEP 1

Assumptions1. The equation is linear in the variable $c$ . . The equation is $6c +1 = -$ .

STEP 2

We need to isolate $c$ on one side of the equation. We can do this by subtracting $1$ from both sides of the equation.
$6c +1 -1 = -2 -1$

STEP 3

implify both sides of the equation.
$6c = -3$

STEP 4

Now, we can solve for $c$ by dividing both sides of the equation by $6$ .
$c = \frac{-3}{6}$

STEP 5

implify the right side of the equation to find the value of $c$ .
$c = -0.5$ The solution to the equation $c +1 = -2$ is $c = -0.5$ .

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QuestionSolve for $c$ in the equation $6 c + 1 = -2$ .

Studdy Solution

STEP 1

Assumptions1. The equation is linear in the variable $c$ . . The equation is $6c +1 = -$ .

STEP 2

We need to isolate $c$ on one side of the equation. We can do this by subtracting $1$ from both sides of the equation.
$6c +1 -1 = -2 -1$

STEP 3

implify both sides of the equation.
$6c = -3$

STEP 4

Now, we can solve for $c$ by dividing both sides of the equation by $6$ .
$c = \frac{-3}{6}$

STEP 5

implify the right side of the equation to find the value of $c$ .
$c = -0.5$ The solution to the equation $c +1 = -2$ is $c = -0.5$ .

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QuestionSolve for ccc in the equation 6c+1=−26 c + 1 = -26c+1=−2.

Studdy Solution

STEP 1

Assumptions1. The equation is linear in the variable ccc. . The equation is 6c+1=−6c +1 = -6c+1=−.

STEP 2

We need to isolate ccc on one side of the equation. We can do this by subtracting 111 from both sides of the equation.6c+1−1=−2−16c +1 -1 = -2 -16c+1−1=−2−1

STEP 3

implify both sides of the equation.6c=−36c = -36c=−3

STEP 4

Now, we can solve for ccc by dividing both sides of the equation by 666.c=−36c = \frac{-3}{6}c=6−3​

STEP 5

implify the right side of the equation to find the value of ccc.c=−0.5c = -0.5c=−0.5The solution to the equation c+1=−2c +1 = -2c+1=−2 is c=−0.5c = -0.5c=−0.5.

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QuestionSolve for $c$ in the equation $6 c + 1 = -2$ .

Assumptions1. The equation is linear in the variable $c$ . . The equation is $6c +1 = -$ .

We need to isolate $c$ on one side of the equation. We can do this by subtracting $1$ from both sides of the equation.
$6c +1 -1 = -2 -1$

implify both sides of the equation.
$6c = -3$

Now, we can solve for $c$ by dividing both sides of the equation by $6$ .
$c = \frac{-3}{6}$

implify the right side of the equation to find the value of $c$ .
$c = -0.5$ The solution to the equation $c +1 = -2$ is $c = -0.5$ .